Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Complete the table shown to the right for the half-life of a certain radioactive substance.

\begin{tabular}{|l|l|}
\hline
Half-Life & Decay Rate, k \\
\hline
3552 years & \\
\hline
\end{tabular}

[tex]\[ k = \][/tex]

(Round to six decimal places as needed.)

Sagot :

To determine the decay rate [tex]\( k \)[/tex] for a radioactive substance given its half-life, we can use the formula for the decay constant in exponential decay processes:

[tex]\[ k = \frac{\ln(2)}{T_{\frac{1}{2}}} \][/tex]

where:
- [tex]\( \ln(2) \)[/tex] is the natural logarithm of 2, which is a constant approximately equal to 0.693.
- [tex]\( T_{\frac{1}{2}} \)[/tex] is the half-life of the substance in years.

Given the half-life [tex]\( T_{\frac{1}{2}} = 3552 \)[/tex] years, we substitute this value into the formula:

[tex]\[ k = \frac{\ln(2)}{3552} \][/tex]
[tex]\[ k = \frac{0.693}{3552} \][/tex]

By performing this division, we find:

[tex]\[ k \approx 0.000195016197 \][/tex]

Rounding this result to six decimal places, we get:

[tex]\[ k \approx 0.000195 \][/tex]

Therefore, the decay rate [tex]\( k \)[/tex] for the half-life of 3552 years is:

[tex]\[ k = 0.000195 \][/tex]

So, the completed table will be:

\begin{tabular}{|l|l|}
\hline
Half-Life & Decay Rate, [tex]\( k \)[/tex] \\
\hline
3552 years & 0.000195 \\
\hline
\end{tabular}