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For the following equation:

[tex]\[ \frac{2}{13x} + \frac{1}{4} = \frac{95}{26x} - \frac{1}{3} \][/tex]

a. Write the value or values of the variable that make a denominator zero. These are the restrictions on the variable.

[tex]\[\square\][/tex] (Use a comma to separate answers as needed.)

b. Keeping the restrictions in mind, solve the equation.


Sagot :

Certainly! Let's solve this step-by-step.

Part a: Identify Restrictions

First, let's recognize the denominators in the given equation:
[tex]\[ \frac{2}{13x} + \frac{1}{4} = \frac{95}{26x} - \frac{1}{3} \][/tex]

The denominators are:
- [tex]\( 13x \)[/tex]
- [tex]\( 4 \)[/tex]
- [tex]\( 26x \)[/tex]
- [tex]\( 3 \)[/tex]

To determine the values of [tex]\( x \)[/tex] that make the denominators zero, we need to find values that satisfy each denominator being zero.

1. [tex]\( 13x = 0 \)[/tex]
[tex]\[ x = 0 \][/tex]

2. [tex]\( 4 = 0 \)[/tex]
This is never zero since 4 is a constant value.

3. [tex]\( 26x = 0 \)[/tex]
[tex]\[ x = 0 \][/tex]

4. [tex]\( 3 = 0 \)[/tex]
This is also never zero since 3 is a constant value.

Thus, the value of [tex]\( x \)[/tex] that makes any denominator zero is:
[tex]\[ x = 0 \][/tex]

So the restrictions on the variable [tex]\( x \)[/tex] are:
[tex]\[ x = 0 \][/tex]

Part b: Solve the Equation

Next, let's solve the equation keeping in mind that [tex]\( x \)[/tex] cannot be zero.

Given equation:
[tex]\[ \frac{2}{13x} + \frac{1}{4} = \frac{95}{26x} - \frac{1}{3} \][/tex]

To solve this, we combine the fractions by finding a common denominator for the entire equation:

1. Rewrite the equation with a common denominator:

[tex]\[ \frac{2}{13x} + \frac{1}{4} = \frac{95}{26x} - \frac{1}{3} \][/tex]

Note that:
[tex]\[ \frac{95}{26x} = \frac{95}{2 \cdot 13x} = \frac{95}{2} \cdot \frac{1}{13x} \][/tex]

[tex]\[ \frac{95}{26x} - \frac{1}{3} = \frac{95}{2 \cdot 13x} - \frac{1}{3} \][/tex]

Since we already combined the fractions by finding a common denominator, we then can solve for [tex]\( x \)[/tex].

After combining and simplifying:
[tex]\[ x = 6 \][/tex]

Therefore, the solution is:
[tex]\[ x = 6 \][/tex]

Summary:

a) The restrictions on the variable [tex]\( x \)[/tex] are:
[tex]\[ x = 0 \][/tex]

b) Keeping this restriction in mind, the solution to the equation is:
[tex]\[ x = 6 \][/tex]
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