Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To balance the given chemical equation: [tex]\( \text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + \text{H}_2\text{O} \)[/tex], let's follow a step-by-step approach:
1. Write down the unbalanced equation:
[tex]\[ \text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + \text{H}_2\text{O} \][/tex]
2. Identify the number of atoms of each element on both sides of the equation:
- Reactants side:
- H (Hydrogen): 1 (from HNO3) + 2 (from Ca(OH)2) = 3
- N (Nitrogen): 1 (from HNO3)
- O (Oxygen): 3 (from HNO3) + 2 (from Ca(OH)2) = 5
- Ca (Calcium): 1 (from Ca(OH)2)
- Products side:
- H (Hydrogen): 2 (from H2O)
- N (Nitrogen): 2 (from Ca(NO3)2)
- O (Oxygen): 6 (from Ca(NO3)2) + 1 (from H2O) = 7
- Ca (Calcium): 1 (from Ca(NO3)2)
3. Balance the atoms one by one:
- Balance Calcium (Ca):
[tex]\(\text{Ca}\)[/tex] is already balanced with 1 atom on each side.
- Balance Nitrogen (N):
There are 1 nitrogen atom on the reactants side and 2 on the products side. Therefore, to balance Nitrogen, we'll need 2 molecules of HNO3 on the reactants side:
[tex]\[ 2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + \text{H}_2\text{O} \][/tex]
- Now, Nitrogen is balanced.
- Balance Oxygen (O):
- On the reactants side: [tex]\(2 \times 3\)[/tex] (from HNO3) + 2 (from Ca(OH)2) = 8
- On the products side: 6 (from Ca(NO3)2) + 1 (from H2O) = 7
Notice that while adding H2O later will balance O and H simultaneously, right now, our O count doesn't balance at 8.
- Balance Hydrogen (H):
- On reactants side, we have: [tex]\(2 \times 1\)[/tex] (from HNO3) + 2 (from Ca(OH)2) = 4
- On products side, we need to balance with water (H2O), which holds two H per molecule.
- Thus, we balance by having 2 water molecules:
[tex]\[ 2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + 2\text{H}_2\text{O} \][/tex]
- Now, Hydrogen is balanced with 4 atoms on each side.
4. Final check:
- Hydrogen: [tex]\(2 \times 1 + 2 = 4\)[/tex] in reactants and [tex]\(2 \times 2 = 4\)[/tex] in products.
- Nitrogen: [tex]\(2\)[/tex] in reactants and [tex]\(2\)[/tex] in products.
- Oxygen: [tex]\(2 \times 3 (HNO3) + 2 (Ca(OH)2) = 8\)[/tex] in reactants and [tex]\(6 (Ca(NO3)2) + 2 (H2O) = 8\)[/tex] in products.
- Calcium: [tex]\(1\)[/tex] in reactants and [tex]\(1\)[/tex] in products.
Thus, the balanced chemical equation is:
[tex]\[ 2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + 2\text{H}_2\text{O} \][/tex]
This indicates that the stoichiometric coefficients for [tex]\( \text{HNO}_3, \text{Ca(OH)}_2, \text{Ca(NO}_3\text{)}_2, \text{H}_2\text{O} \)[/tex] are [tex]\( 2, 1, 1, 2 \)[/tex] respectively.
1. Write down the unbalanced equation:
[tex]\[ \text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + \text{H}_2\text{O} \][/tex]
2. Identify the number of atoms of each element on both sides of the equation:
- Reactants side:
- H (Hydrogen): 1 (from HNO3) + 2 (from Ca(OH)2) = 3
- N (Nitrogen): 1 (from HNO3)
- O (Oxygen): 3 (from HNO3) + 2 (from Ca(OH)2) = 5
- Ca (Calcium): 1 (from Ca(OH)2)
- Products side:
- H (Hydrogen): 2 (from H2O)
- N (Nitrogen): 2 (from Ca(NO3)2)
- O (Oxygen): 6 (from Ca(NO3)2) + 1 (from H2O) = 7
- Ca (Calcium): 1 (from Ca(NO3)2)
3. Balance the atoms one by one:
- Balance Calcium (Ca):
[tex]\(\text{Ca}\)[/tex] is already balanced with 1 atom on each side.
- Balance Nitrogen (N):
There are 1 nitrogen atom on the reactants side and 2 on the products side. Therefore, to balance Nitrogen, we'll need 2 molecules of HNO3 on the reactants side:
[tex]\[ 2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + \text{H}_2\text{O} \][/tex]
- Now, Nitrogen is balanced.
- Balance Oxygen (O):
- On the reactants side: [tex]\(2 \times 3\)[/tex] (from HNO3) + 2 (from Ca(OH)2) = 8
- On the products side: 6 (from Ca(NO3)2) + 1 (from H2O) = 7
Notice that while adding H2O later will balance O and H simultaneously, right now, our O count doesn't balance at 8.
- Balance Hydrogen (H):
- On reactants side, we have: [tex]\(2 \times 1\)[/tex] (from HNO3) + 2 (from Ca(OH)2) = 4
- On products side, we need to balance with water (H2O), which holds two H per molecule.
- Thus, we balance by having 2 water molecules:
[tex]\[ 2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + 2\text{H}_2\text{O} \][/tex]
- Now, Hydrogen is balanced with 4 atoms on each side.
4. Final check:
- Hydrogen: [tex]\(2 \times 1 + 2 = 4\)[/tex] in reactants and [tex]\(2 \times 2 = 4\)[/tex] in products.
- Nitrogen: [tex]\(2\)[/tex] in reactants and [tex]\(2\)[/tex] in products.
- Oxygen: [tex]\(2 \times 3 (HNO3) + 2 (Ca(OH)2) = 8\)[/tex] in reactants and [tex]\(6 (Ca(NO3)2) + 2 (H2O) = 8\)[/tex] in products.
- Calcium: [tex]\(1\)[/tex] in reactants and [tex]\(1\)[/tex] in products.
Thus, the balanced chemical equation is:
[tex]\[ 2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3\text{)}_2 + 2\text{H}_2\text{O} \][/tex]
This indicates that the stoichiometric coefficients for [tex]\( \text{HNO}_3, \text{Ca(OH)}_2, \text{Ca(NO}_3\text{)}_2, \text{H}_2\text{O} \)[/tex] are [tex]\( 2, 1, 1, 2 \)[/tex] respectively.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
