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Sagot :
To find [tex]\( f(3) \)[/tex] for the function [tex]\( f(x) = -5x^2 - x + 20 \)[/tex], follow these steps:
1. Substitute [tex]\( x = 3 \)[/tex] into the function:
[tex]\[ f(3) = -5(3)^2 - 3 + 20 \][/tex]
2. Calculate the square of 3:
[tex]\[ 3^2 = 9 \][/tex]
3. Multiply the squared value by -5:
[tex]\[ -5 \cdot 9 = -45 \][/tex]
4. Add the linear term (-3):
[tex]\[ -45 - 3 = -48 \][/tex]
5. Finally, add the constant term (20):
[tex]\[ -48 + 20 = -28 \][/tex]
Thus, the value of [tex]\( f(3) \)[/tex] is [tex]\(-28\)[/tex].
The correct answer is [tex]\(\boxed{-28}\)[/tex].
1. Substitute [tex]\( x = 3 \)[/tex] into the function:
[tex]\[ f(3) = -5(3)^2 - 3 + 20 \][/tex]
2. Calculate the square of 3:
[tex]\[ 3^2 = 9 \][/tex]
3. Multiply the squared value by -5:
[tex]\[ -5 \cdot 9 = -45 \][/tex]
4. Add the linear term (-3):
[tex]\[ -45 - 3 = -48 \][/tex]
5. Finally, add the constant term (20):
[tex]\[ -48 + 20 = -28 \][/tex]
Thus, the value of [tex]\( f(3) \)[/tex] is [tex]\(-28\)[/tex].
The correct answer is [tex]\(\boxed{-28}\)[/tex].
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