Answered

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Use the following table to answer the question.

\begin{tabular}{|l|l|l|l|}
\hline Strong acids & Weak acids & Weak bases & Strong bases \\
\hline HBr & [tex]$CH _3 COOH$[/tex] & [tex]$NH _3$[/tex] & NaOH \\
\hline [tex]$HNO _3$[/tex] & HF & [tex]$NH _4 OH$[/tex] & KOH \\
\hline [tex]$H _2 SO _4$[/tex] & HCN & & [tex]$Ca ( OH )_2$[/tex] \\
\hline
\end{tabular}

Which reaction would yield a neutral salt?

A. [tex]$2 NaOH + H _2 SO _4$[/tex]
B. [tex]$NaOH + HCN$[/tex]
C. [tex]$KOH + HF$[/tex]
D. [tex]$2 NH _4 OH + H _2 SO _4$[/tex]

Sagot :

GinnyAnswer
To determine which reaction yields a neutral salt, we need to identify if the reaction involves both a strong acid and a strong base. A neutral salt is typically formed when a strong acid reacts with a strong base.

Let's analyze each reaction given:

1. [tex]\(2 \text{NaOH} + \text{H}_2\text{SO}_4\)[/tex]
- NaOH is listed as a strong base.
- [tex]\( \text{H}_2\text{SO}_4 \)[/tex] is listed as a strong acid.
- A reaction between a strong base and a strong acid will yield a neutral salt.

2. [tex]\( \text{NaOH} + \text{HCN} \)[/tex]
- NaOH is listed as a strong base.
- [tex]\( \text{HCN} \)[/tex] is listed as a weak acid.
- A reaction between a strong base and a weak acid will not yield a neutral salt.

3. [tex]\( \text{KOH} + \text{HF} \)[/tex]
- KOH is listed as a strong base.
- HF is listed as a weak acid.
- A reaction between a strong base and a weak acid will not yield a neutral salt.

4. [tex]\(2 \text{NH}_4\text{OH} + \text{H}_2\text{SO}_4\)[/tex]
- [tex]\( \text{NH}_4\text{OH} \)[/tex] is listed as a weak base.
- [tex]\( \text{H}_2\text{SO}_4 \)[/tex] is listed as a strong acid.
- A reaction between a weak base and a strong acid will not yield a neutral salt.

Only the first reaction involves both a strong acid and a strong base. Therefore, only the first reaction will yield a neutral salt.

The reaction that would yield a neutral salt is:
[tex]\[ 2 \text{NaOH} + \text{H}_2\text{SO}_4 \][/tex]

This corresponds to the first reaction in the given list. So, the correct answer is:

1. [tex]\(2 \text{NaOH} + \text{H}_2\text{SO}_4 \)[/tex]
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