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Use the compound interest formulas [tex]A = P \left(1 + \frac{r}{n}\right)^{nt}[/tex] and [tex]A = Pe^{rt}[/tex] to solve the problem given. Round answers to the nearest cent.

Find the accumulated value of an investment of [tex]\$15,000[/tex] for 4 years at an interest rate of [tex]6.5\%[/tex].

a. What is the accumulated value if the money is compounded semiannually?

b. What is the accumulated value if the money is compounded monthly?

c. What is the accumulated value if the money is compounded continuously?

(Round your answer to the nearest cent. Do not include the [tex]\$[/tex] symbol in your answer.)


Sagot :

To find the accumulated value of an investment of [tex]$15,000 for 4 years at an interest rate of 6.5% when the money is compounded semiannually, we'll use the compound interest formula: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( P \) is the principal amount ($[/tex]15,000),
- [tex]\( r \)[/tex] is the annual interest rate (0.065 as a decimal),
- [tex]\( n \)[/tex] is the number of times the interest is compounded per year (2 for semiannual compounding),
- [tex]\( t \)[/tex] is the time the money is invested for (4 years).

Plugging in the values, we get:

[tex]\[ A = 15000 \left(1 + \frac{0.065}{2}\right)^{2 \cdot 4} \][/tex]
[tex]\[ A = 15000 \left(1 + 0.0325\right)^{8} \][/tex]
[tex]\[ A = 15000 \left(1.0325\right)^{8} \][/tex]

Now, we compute the value:

[tex]\[ A \approx 15000 \left(1.297578453\right) \][/tex]
[tex]\[ A \approx 19453.95 \][/tex]

Rounding the above value to the nearest cent, we get:

[tex]\[ A = 19373.66 \][/tex]

Therefore, the accumulated value of the investment compounded semiannually is [tex]$\boxed{19373.66}$[/tex].
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