Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To solve the inequality [tex]\(4x^2 - 25 < 0\)[/tex], follow these detailed steps:
1. Rewrite the inequality:
Start with the given inequality:
[tex]\[ 4x^2 - 25 < 0 \][/tex]
2. Rewrite it as a quadratic equation:
Consider the corresponding equation:
[tex]\[ 4x^2 - 25 = 0 \][/tex]
3. Factorize the quadratic equation:
You can factorize [tex]\(4x^2 - 25\)[/tex] as a difference of squares:
[tex]\[ 4x^2 - 25 = (2x - 5)(2x + 5) \][/tex]
So the equation becomes:
[tex]\[ (2x - 5)(2x + 5) = 0 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
Set each factor equal to zero and solve for [tex]\(x\)[/tex]:
[tex]\[ 2x - 5 = 0 \quad \text{or} \quad 2x + 5 = 0 \][/tex]
Solving these gives:
[tex]\[ 2x = 5 \quad \text{or} \quad 2x = -5 \][/tex]
So,
[tex]\[ x = \frac{5}{2} \quad \text{or} \quad x = \frac{-5}{2} \][/tex]
Therefore, [tex]\(x = 2.5\)[/tex] or [tex]\(x = -2.5\)[/tex].
5. Determine intervals to check the signs:
Based on the roots [tex]\(x = 2.5\)[/tex] and [tex]\(x = -2.5\)[/tex], divide the number line into intervals:
[tex]\[ (-\infty, -2.5), \quad (-2.5, 2.5), \quad (2.5, \infty) \][/tex]
6. Test points in the intervals to see where the inequality is satisfied:
- For the interval [tex]\((-∞, -2.5)\)[/tex]:
Choose a test point, say [tex]\(x = -3\)[/tex]:
[tex]\[ 4(-3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
- For the interval [tex]\((-2.5, 2.5)\)[/tex]:
Choose a test point, say [tex]\(x = 0\)[/tex]:
[tex]\[ 4(0)^2 - 25 = 0 - 25 = -25 \][/tex]
Since -25 is less than 0, this interval satisfies the inequality.
- For the interval [tex]\((2.5, ∞)\)[/tex]:
Choose a test point, say [tex]\(x = 3\)[/tex]:
[tex]\[ 4(3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
7. Determine which intervals satisfy the inequality:
From the interval test, the single interval that satisfies the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ (-2.5, 2.5) \][/tex]
So, the solution to the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ -2.5 < x < 2.5 \][/tex]
1. Rewrite the inequality:
Start with the given inequality:
[tex]\[ 4x^2 - 25 < 0 \][/tex]
2. Rewrite it as a quadratic equation:
Consider the corresponding equation:
[tex]\[ 4x^2 - 25 = 0 \][/tex]
3. Factorize the quadratic equation:
You can factorize [tex]\(4x^2 - 25\)[/tex] as a difference of squares:
[tex]\[ 4x^2 - 25 = (2x - 5)(2x + 5) \][/tex]
So the equation becomes:
[tex]\[ (2x - 5)(2x + 5) = 0 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
Set each factor equal to zero and solve for [tex]\(x\)[/tex]:
[tex]\[ 2x - 5 = 0 \quad \text{or} \quad 2x + 5 = 0 \][/tex]
Solving these gives:
[tex]\[ 2x = 5 \quad \text{or} \quad 2x = -5 \][/tex]
So,
[tex]\[ x = \frac{5}{2} \quad \text{or} \quad x = \frac{-5}{2} \][/tex]
Therefore, [tex]\(x = 2.5\)[/tex] or [tex]\(x = -2.5\)[/tex].
5. Determine intervals to check the signs:
Based on the roots [tex]\(x = 2.5\)[/tex] and [tex]\(x = -2.5\)[/tex], divide the number line into intervals:
[tex]\[ (-\infty, -2.5), \quad (-2.5, 2.5), \quad (2.5, \infty) \][/tex]
6. Test points in the intervals to see where the inequality is satisfied:
- For the interval [tex]\((-∞, -2.5)\)[/tex]:
Choose a test point, say [tex]\(x = -3\)[/tex]:
[tex]\[ 4(-3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
- For the interval [tex]\((-2.5, 2.5)\)[/tex]:
Choose a test point, say [tex]\(x = 0\)[/tex]:
[tex]\[ 4(0)^2 - 25 = 0 - 25 = -25 \][/tex]
Since -25 is less than 0, this interval satisfies the inequality.
- For the interval [tex]\((2.5, ∞)\)[/tex]:
Choose a test point, say [tex]\(x = 3\)[/tex]:
[tex]\[ 4(3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
7. Determine which intervals satisfy the inequality:
From the interval test, the single interval that satisfies the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ (-2.5, 2.5) \][/tex]
So, the solution to the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ -2.5 < x < 2.5 \][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.