Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To solve the inequality [tex]\(4x^2 - 25 < 0\)[/tex], follow these detailed steps:
1. Rewrite the inequality:
Start with the given inequality:
[tex]\[ 4x^2 - 25 < 0 \][/tex]
2. Rewrite it as a quadratic equation:
Consider the corresponding equation:
[tex]\[ 4x^2 - 25 = 0 \][/tex]
3. Factorize the quadratic equation:
You can factorize [tex]\(4x^2 - 25\)[/tex] as a difference of squares:
[tex]\[ 4x^2 - 25 = (2x - 5)(2x + 5) \][/tex]
So the equation becomes:
[tex]\[ (2x - 5)(2x + 5) = 0 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
Set each factor equal to zero and solve for [tex]\(x\)[/tex]:
[tex]\[ 2x - 5 = 0 \quad \text{or} \quad 2x + 5 = 0 \][/tex]
Solving these gives:
[tex]\[ 2x = 5 \quad \text{or} \quad 2x = -5 \][/tex]
So,
[tex]\[ x = \frac{5}{2} \quad \text{or} \quad x = \frac{-5}{2} \][/tex]
Therefore, [tex]\(x = 2.5\)[/tex] or [tex]\(x = -2.5\)[/tex].
5. Determine intervals to check the signs:
Based on the roots [tex]\(x = 2.5\)[/tex] and [tex]\(x = -2.5\)[/tex], divide the number line into intervals:
[tex]\[ (-\infty, -2.5), \quad (-2.5, 2.5), \quad (2.5, \infty) \][/tex]
6. Test points in the intervals to see where the inequality is satisfied:
- For the interval [tex]\((-∞, -2.5)\)[/tex]:
Choose a test point, say [tex]\(x = -3\)[/tex]:
[tex]\[ 4(-3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
- For the interval [tex]\((-2.5, 2.5)\)[/tex]:
Choose a test point, say [tex]\(x = 0\)[/tex]:
[tex]\[ 4(0)^2 - 25 = 0 - 25 = -25 \][/tex]
Since -25 is less than 0, this interval satisfies the inequality.
- For the interval [tex]\((2.5, ∞)\)[/tex]:
Choose a test point, say [tex]\(x = 3\)[/tex]:
[tex]\[ 4(3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
7. Determine which intervals satisfy the inequality:
From the interval test, the single interval that satisfies the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ (-2.5, 2.5) \][/tex]
So, the solution to the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ -2.5 < x < 2.5 \][/tex]
1. Rewrite the inequality:
Start with the given inequality:
[tex]\[ 4x^2 - 25 < 0 \][/tex]
2. Rewrite it as a quadratic equation:
Consider the corresponding equation:
[tex]\[ 4x^2 - 25 = 0 \][/tex]
3. Factorize the quadratic equation:
You can factorize [tex]\(4x^2 - 25\)[/tex] as a difference of squares:
[tex]\[ 4x^2 - 25 = (2x - 5)(2x + 5) \][/tex]
So the equation becomes:
[tex]\[ (2x - 5)(2x + 5) = 0 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
Set each factor equal to zero and solve for [tex]\(x\)[/tex]:
[tex]\[ 2x - 5 = 0 \quad \text{or} \quad 2x + 5 = 0 \][/tex]
Solving these gives:
[tex]\[ 2x = 5 \quad \text{or} \quad 2x = -5 \][/tex]
So,
[tex]\[ x = \frac{5}{2} \quad \text{or} \quad x = \frac{-5}{2} \][/tex]
Therefore, [tex]\(x = 2.5\)[/tex] or [tex]\(x = -2.5\)[/tex].
5. Determine intervals to check the signs:
Based on the roots [tex]\(x = 2.5\)[/tex] and [tex]\(x = -2.5\)[/tex], divide the number line into intervals:
[tex]\[ (-\infty, -2.5), \quad (-2.5, 2.5), \quad (2.5, \infty) \][/tex]
6. Test points in the intervals to see where the inequality is satisfied:
- For the interval [tex]\((-∞, -2.5)\)[/tex]:
Choose a test point, say [tex]\(x = -3\)[/tex]:
[tex]\[ 4(-3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
- For the interval [tex]\((-2.5, 2.5)\)[/tex]:
Choose a test point, say [tex]\(x = 0\)[/tex]:
[tex]\[ 4(0)^2 - 25 = 0 - 25 = -25 \][/tex]
Since -25 is less than 0, this interval satisfies the inequality.
- For the interval [tex]\((2.5, ∞)\)[/tex]:
Choose a test point, say [tex]\(x = 3\)[/tex]:
[tex]\[ 4(3)^2 - 25 = 4(9) - 25 = 36 - 25 = 11 \][/tex]
Since 11 is greater than 0, this interval does not satisfy the inequality.
7. Determine which intervals satisfy the inequality:
From the interval test, the single interval that satisfies the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ (-2.5, 2.5) \][/tex]
So, the solution to the inequality [tex]\(4x^2 - 25 < 0\)[/tex] is:
[tex]\[ -2.5 < x < 2.5 \][/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.