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A student rolls two non-standard number cubes, each with the numbers 1 through 3 on it. Use the results in the frequency table below to determine the experimental probability of rolling two numbers with a sum of 4. Order does not matter.

\begin{tabular}{|l|c|c|c|c|c|c|}
\hline Result & 1.1 & 1.2 & 2.2 & 1.3 & 2.3 & 3.3 \\
\hline Frequency & 9 & 8 & 10 & 5 & 7 & 8 \\
\hline
\end{tabular}

A. [tex]$\frac{5}{47}$[/tex]
B. [tex]$1 \frac{3}{47}$[/tex]
C. [tex]$\frac{15}{47}$[/tex]
D. 15


Sagot :

To determine the experimental probability of rolling two numbers that sum to 4, we'll go through the following steps:

1. Identify Possible Outcomes for a Sum of 4:
- We need to consider the pairs of numbers from two dice that sum to 4. These pairs are:
- (1, 3)
- (2, 2)
- (3, 1)
Since order does not matter, we will consider (3, 1) and (1, 3) only once.

2. Frequency of Relevant Outcomes:
- From the given frequency table:
- Frequency of (1, 3) = 5
- Frequency of (2, 2) = 10

3. Total Frequency for Sum of 4:
- Add the frequencies of the outcomes that sum to 4:
[tex]\[ \text{frequency\_sum\_of\_4} = 5 + 10 = 15 \][/tex]

4. Calculate Total Number of Rolls:
- Sum all the frequencies in the table to get the total number of rolls:
[tex]\[ \text{total\_rolls} = 9 + 8 + 10 + 5 + 7 + 8 = 47 \][/tex]

5. Calculate the Experimental Probability:
- The experimental probability is the frequency of the desired outcome divided by the total number of rolls:
[tex]\[ \text{experimental\_probability} = \frac{\text{frequency\_sum\_of\_4}}{\text{total\_rolls}} = \frac{15}{47} \][/tex]

6. Verify the Answer in Fraction Form:
- The correct fraction for the experimental probability is:
[tex]\[ \frac{15}{47} \][/tex]

### Conclusion:
The experimental probability of rolling two numbers that sum to 4 is [tex]\(\frac{15}{47}\)[/tex]. This corresponds to one of the given choices, verifying that the right answer is indeed [tex]\(\frac{15}{47}\)[/tex].