Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Let's analyze the function [tex]\( f(x) = 3(2.5)^x \)[/tex] in detail to determine its properties.
1. Is the function increasing?
- To determine if the function is increasing, we look at the derivative [tex]\( f'(x) \)[/tex]. A function is increasing if its derivative is greater than zero for all x. In the given situation, the function [tex]\( 3(2.5)^x \)[/tex] is not strictly increasing.
2. Initial Value:
- To find the initial value, we simply evaluate the function at [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 3(2.5)^0 = 3 \times 1 = 3 \][/tex]
- So, the initial value of the function is [tex]\( 3 \)[/tex].
3. Limit as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex]:
- We consider the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches positive infinity. The expression [tex]\( (2.5)^x \)[/tex] grows without bound as [tex]\( x \)[/tex] increases. Hence:
[tex]\[ \lim_{x \to +\infty} f(x) = \lim_{x \to +\infty} 3(2.5)^x = +\infty \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches positive infinity is [tex]\( \infty \)[/tex].
4. Limit as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex]:
- For the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches negative infinity, note that [tex]\( (2.5)^x \)[/tex] tends towards zero since any base greater than one raised to a sufficiently large negative power approaches zero. Thus:
[tex]\[ \lim_{x \to -\infty} f(x) = \lim_{x \to -\infty} 3(2.5)^x = 3 \times 0 = 0 \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches negative infinity is [tex]\( 0 \)[/tex].
Given these results:
1. The function is not increasing.
2. The initial value of the function [tex]\( f(0) \)[/tex] is [tex]\( 3 \)[/tex].
3. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex] is [tex]\( +\infty \)[/tex].
4. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex] is [tex]\( 0 \)[/tex].
These results match the true statements about the function [tex]\( f(x) = 3(2.5)^x \)[/tex].
1. Is the function increasing?
- To determine if the function is increasing, we look at the derivative [tex]\( f'(x) \)[/tex]. A function is increasing if its derivative is greater than zero for all x. In the given situation, the function [tex]\( 3(2.5)^x \)[/tex] is not strictly increasing.
2. Initial Value:
- To find the initial value, we simply evaluate the function at [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 3(2.5)^0 = 3 \times 1 = 3 \][/tex]
- So, the initial value of the function is [tex]\( 3 \)[/tex].
3. Limit as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex]:
- We consider the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches positive infinity. The expression [tex]\( (2.5)^x \)[/tex] grows without bound as [tex]\( x \)[/tex] increases. Hence:
[tex]\[ \lim_{x \to +\infty} f(x) = \lim_{x \to +\infty} 3(2.5)^x = +\infty \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches positive infinity is [tex]\( \infty \)[/tex].
4. Limit as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex]:
- For the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches negative infinity, note that [tex]\( (2.5)^x \)[/tex] tends towards zero since any base greater than one raised to a sufficiently large negative power approaches zero. Thus:
[tex]\[ \lim_{x \to -\infty} f(x) = \lim_{x \to -\infty} 3(2.5)^x = 3 \times 0 = 0 \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches negative infinity is [tex]\( 0 \)[/tex].
Given these results:
1. The function is not increasing.
2. The initial value of the function [tex]\( f(0) \)[/tex] is [tex]\( 3 \)[/tex].
3. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex] is [tex]\( +\infty \)[/tex].
4. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex] is [tex]\( 0 \)[/tex].
These results match the true statements about the function [tex]\( f(x) = 3(2.5)^x \)[/tex].
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.