Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Let's analyze the function [tex]\( f(x) = 3(2.5)^x \)[/tex] in detail to determine its properties.
1. Is the function increasing?
- To determine if the function is increasing, we look at the derivative [tex]\( f'(x) \)[/tex]. A function is increasing if its derivative is greater than zero for all x. In the given situation, the function [tex]\( 3(2.5)^x \)[/tex] is not strictly increasing.
2. Initial Value:
- To find the initial value, we simply evaluate the function at [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 3(2.5)^0 = 3 \times 1 = 3 \][/tex]
- So, the initial value of the function is [tex]\( 3 \)[/tex].
3. Limit as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex]:
- We consider the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches positive infinity. The expression [tex]\( (2.5)^x \)[/tex] grows without bound as [tex]\( x \)[/tex] increases. Hence:
[tex]\[ \lim_{x \to +\infty} f(x) = \lim_{x \to +\infty} 3(2.5)^x = +\infty \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches positive infinity is [tex]\( \infty \)[/tex].
4. Limit as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex]:
- For the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches negative infinity, note that [tex]\( (2.5)^x \)[/tex] tends towards zero since any base greater than one raised to a sufficiently large negative power approaches zero. Thus:
[tex]\[ \lim_{x \to -\infty} f(x) = \lim_{x \to -\infty} 3(2.5)^x = 3 \times 0 = 0 \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches negative infinity is [tex]\( 0 \)[/tex].
Given these results:
1. The function is not increasing.
2. The initial value of the function [tex]\( f(0) \)[/tex] is [tex]\( 3 \)[/tex].
3. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex] is [tex]\( +\infty \)[/tex].
4. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex] is [tex]\( 0 \)[/tex].
These results match the true statements about the function [tex]\( f(x) = 3(2.5)^x \)[/tex].
1. Is the function increasing?
- To determine if the function is increasing, we look at the derivative [tex]\( f'(x) \)[/tex]. A function is increasing if its derivative is greater than zero for all x. In the given situation, the function [tex]\( 3(2.5)^x \)[/tex] is not strictly increasing.
2. Initial Value:
- To find the initial value, we simply evaluate the function at [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 3(2.5)^0 = 3 \times 1 = 3 \][/tex]
- So, the initial value of the function is [tex]\( 3 \)[/tex].
3. Limit as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex]:
- We consider the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches positive infinity. The expression [tex]\( (2.5)^x \)[/tex] grows without bound as [tex]\( x \)[/tex] increases. Hence:
[tex]\[ \lim_{x \to +\infty} f(x) = \lim_{x \to +\infty} 3(2.5)^x = +\infty \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches positive infinity is [tex]\( \infty \)[/tex].
4. Limit as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex]:
- For the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches negative infinity, note that [tex]\( (2.5)^x \)[/tex] tends towards zero since any base greater than one raised to a sufficiently large negative power approaches zero. Thus:
[tex]\[ \lim_{x \to -\infty} f(x) = \lim_{x \to -\infty} 3(2.5)^x = 3 \times 0 = 0 \][/tex]
- Therefore, the limit of the function as [tex]\( x \)[/tex] approaches negative infinity is [tex]\( 0 \)[/tex].
Given these results:
1. The function is not increasing.
2. The initial value of the function [tex]\( f(0) \)[/tex] is [tex]\( 3 \)[/tex].
3. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex] is [tex]\( +\infty \)[/tex].
4. The limit of the function as [tex]\( x \)[/tex] approaches [tex]\( -\infty \)[/tex] is [tex]\( 0 \)[/tex].
These results match the true statements about the function [tex]\( f(x) = 3(2.5)^x \)[/tex].
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.