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Investments increase exponentially by about [tex]60\%[/tex] every 6 years. If you start with a [tex]\$2500[/tex] investment, how much money would you have after 18 years?

Future Amount = [tex]I(1 + r)^t[/tex]

Calculate the future amount.

Sagot :

Sure! Let's solve this problem step-by-step.

### Step 1: Understanding the Parameters
- Initial Investment (I): [tex]$2500 - Rate of Increase (r): 60% or 0.60 - Total Time (t_years): 18 years - Period (t_period): 6 years ### Step 2: Number of Periods First, we need to determine how many 6-year periods fit into 18 years. \[ \text{Number of periods} = \frac{\text{Total Time (t_years)}}{\text{Period (t_period)}} \] Plugging in the values: \[ \text{Number of periods} = \frac{18 \ \text{years}}{6 \ \text{years/period}} = 3 \] ### Step 3: Future Amount Calculation Next, we will use the formula for exponential increase: \[ \text{Future Amount} = \text{Initial Investment} \times (1 + \text{Rate of Increase})^{\text{Number of Periods}} \] Substitute the given values: \[ \text{Future Amount} = 2500 \times (1 + 0.60)^3 \] ### Step 4: Solving the Equation Now, calculate the factor of the exponential increase: \[ \text{Future Amount} = 2500 \times (1.60)^3 \] ### Step 5: Final Calculation Performing the multiplication: \[ \text{Future Amount} = 2500 \times 4.096 = 10240 \] Therefore, after 18 years, your investment would grow to approximately $[/tex]10,240.00.
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