Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To classify each expression as either a real number or a complex number, let us examine them individually:
1. [tex]\(\sqrt{(-3)^2}\)[/tex]:
- Calculate [tex]\( (-3)^2 \)[/tex]: [tex]\( (-3)^2 = 9 \)[/tex].
- Then, take the square root of 9: [tex]\( \sqrt{9} = 3 \)[/tex].
- This is a real number.
2. [tex]\( -2 + 5i \)[/tex]:
- This expression has both a real part ([tex]\(-2\)[/tex]) and an imaginary part ([tex]\(5i\)[/tex]).
- This is a complex number.
3. [tex]\( i^4 \)[/tex]:
- Considering the powers of [tex]\( i \)[/tex]:
- [tex]\( i^2 = -1 \)[/tex]
- [tex]\( i^4 = (i^2)^2 = (-1)^2 = 1 \)[/tex]
- This is a real number.
4. [tex]\( \sqrt{-3} \)[/tex]:
- The square root of a negative number involves [tex]\( i \)[/tex].
- Specifically, [tex]\( \sqrt{-3} = \sqrt{3}i \)[/tex].
- This is a complex number.
5. [tex]\( 7i^2 + 6i^3 \)[/tex]:
- Calculate [tex]\( i^2 \)[/tex]: [tex]\( i^2 = -1 \)[/tex].
- Calculate [tex]\( i^3 \)[/tex]: [tex]\( i^3 = i^2 \cdot i = -i \)[/tex].
- So, [tex]\( 7i^2 = 7(-1) = -7 \)[/tex].
- And, [tex]\( 6i^3 = 6(-i) = -6i \)[/tex].
- Combining: [tex]\( 7i^2 + 6i^3 = -7 - 6i \)[/tex].
- This is a complex number.
6. [tex]\( 0 + 4i \)[/tex]:
- This expression resembles the form [tex]\( a + bi \)[/tex] with [tex]\( a = 0 \)[/tex] and [tex]\( b = 4 \)[/tex].
- This is a complex number.
7. [tex]\( -1 + 3i^2 \)[/tex]:
- Considering [tex]\( i^2 = -1 \)[/tex]:
- Calculate [tex]\( 3i^2 \)[/tex]: [tex]\( 3 \cdot (-1) = -3 \)[/tex].
- So, the expression becomes [tex]\( -1 + (-3) = -4 \)[/tex].
- This is a real number.
8. 409:
- This is a plain real number (an integer).
- This is a real number.
Now, organizing the expressions into their respective categories:
[tex]\[ \begin{tabular}{|l|l|} \hline Real Numbers & Complex Numbers \\ \hline & \\ \sqrt{(-3)^2} & -2 + 5i \\ i^4 & \sqrt{-3} \\ -1 + 3i^2 & 7i^2 + 6i^3 \\ 409 & 0 + 4i \\ & \\ \hline \end{tabular} \][/tex]
So, the final table should be:
[tex]\[ \begin{tabular}{|l|l|} \hline Real Numbers & Complex Numbers \\ \hline \sqrt{(-3)^2} & -2 + 5i \\ i^4 & \sqrt{-3} \\ -1 + 3i^2 & 7i^2 + 6i^3 \\ 409 & 0 + 4i \\ \hline \end{tabular} \][/tex]
1. [tex]\(\sqrt{(-3)^2}\)[/tex]:
- Calculate [tex]\( (-3)^2 \)[/tex]: [tex]\( (-3)^2 = 9 \)[/tex].
- Then, take the square root of 9: [tex]\( \sqrt{9} = 3 \)[/tex].
- This is a real number.
2. [tex]\( -2 + 5i \)[/tex]:
- This expression has both a real part ([tex]\(-2\)[/tex]) and an imaginary part ([tex]\(5i\)[/tex]).
- This is a complex number.
3. [tex]\( i^4 \)[/tex]:
- Considering the powers of [tex]\( i \)[/tex]:
- [tex]\( i^2 = -1 \)[/tex]
- [tex]\( i^4 = (i^2)^2 = (-1)^2 = 1 \)[/tex]
- This is a real number.
4. [tex]\( \sqrt{-3} \)[/tex]:
- The square root of a negative number involves [tex]\( i \)[/tex].
- Specifically, [tex]\( \sqrt{-3} = \sqrt{3}i \)[/tex].
- This is a complex number.
5. [tex]\( 7i^2 + 6i^3 \)[/tex]:
- Calculate [tex]\( i^2 \)[/tex]: [tex]\( i^2 = -1 \)[/tex].
- Calculate [tex]\( i^3 \)[/tex]: [tex]\( i^3 = i^2 \cdot i = -i \)[/tex].
- So, [tex]\( 7i^2 = 7(-1) = -7 \)[/tex].
- And, [tex]\( 6i^3 = 6(-i) = -6i \)[/tex].
- Combining: [tex]\( 7i^2 + 6i^3 = -7 - 6i \)[/tex].
- This is a complex number.
6. [tex]\( 0 + 4i \)[/tex]:
- This expression resembles the form [tex]\( a + bi \)[/tex] with [tex]\( a = 0 \)[/tex] and [tex]\( b = 4 \)[/tex].
- This is a complex number.
7. [tex]\( -1 + 3i^2 \)[/tex]:
- Considering [tex]\( i^2 = -1 \)[/tex]:
- Calculate [tex]\( 3i^2 \)[/tex]: [tex]\( 3 \cdot (-1) = -3 \)[/tex].
- So, the expression becomes [tex]\( -1 + (-3) = -4 \)[/tex].
- This is a real number.
8. 409:
- This is a plain real number (an integer).
- This is a real number.
Now, organizing the expressions into their respective categories:
[tex]\[ \begin{tabular}{|l|l|} \hline Real Numbers & Complex Numbers \\ \hline & \\ \sqrt{(-3)^2} & -2 + 5i \\ i^4 & \sqrt{-3} \\ -1 + 3i^2 & 7i^2 + 6i^3 \\ 409 & 0 + 4i \\ & \\ \hline \end{tabular} \][/tex]
So, the final table should be:
[tex]\[ \begin{tabular}{|l|l|} \hline Real Numbers & Complex Numbers \\ \hline \sqrt{(-3)^2} & -2 + 5i \\ i^4 & \sqrt{-3} \\ -1 + 3i^2 & 7i^2 + 6i^3 \\ 409 & 0 + 4i \\ \hline \end{tabular} \][/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.