Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine the end behavior of the polynomial function [tex]\( f(x) = 2x^3 - 26x - 24 \)[/tex], we analyze the dominating term of the polynomial as [tex]\( x \)[/tex] becomes very large positively ([tex]\( x \rightarrow \infty \)[/tex]) and very large negatively ([tex]\( x \rightarrow -\infty \)[/tex]).
### Analyzing as [tex]\( x \to \infty \)[/tex]:
1. The leading term of the polynomial is [tex]\( 2x^3 \)[/tex].
2. As [tex]\( x \to \infty \)[/tex], the term [tex]\( 2x^3 \)[/tex] dominates all other terms.
3. Since [tex]\( 2x^3 \)[/tex] grows very large and positive as [tex]\( x \to \infty \)[/tex] (because the coefficient 2 is positive), [tex]\( f(x) \to \infty \)[/tex] as [tex]\( x \to \infty \)[/tex].
### Analyzing as [tex]\( x \to -\infty \)[/tex]:
1. Again, consider the leading term [tex]\( 2x^3 \)[/tex].
2. As [tex]\( x \to -\infty \)[/tex], [tex]\( (-x)^3 = -x^3 \)[/tex] becomes very large and negative.
3. So [tex]\( 2(-x^3) = -2x^3 \)[/tex] also grows very large and negative as [tex]\( x \to -\infty \)[/tex], which means [tex]\( f(x) \to -\infty \)[/tex] as [tex]\( x \to -\infty \)[/tex].
Given these analyses, we conclude:
- As [tex]\( x \to \infty \)[/tex], [tex]\( y \to \infty \)[/tex].
- As [tex]\( x \to -\infty \)[/tex], [tex]\( y \to -\infty \)[/tex].
Therefore, the correct description for the end behavior of the polynomial [tex]\( f(x) = 2x^3 - 26x - 24 \)[/tex] is:
- As [tex]\( x \rightarrow -\infty, y \rightarrow -\infty \)[/tex] and as [tex]\( x \rightarrow \infty, y \rightarrow \infty \)[/tex].
Thus, the answer aligns with the second given option:
- As [tex]\( x \rightarrow -\infty, y \rightarrow -\infty \)[/tex] and as [tex]\( x \rightarrow \infty, y \rightarrow \infty \)[/tex].
### Analyzing as [tex]\( x \to \infty \)[/tex]:
1. The leading term of the polynomial is [tex]\( 2x^3 \)[/tex].
2. As [tex]\( x \to \infty \)[/tex], the term [tex]\( 2x^3 \)[/tex] dominates all other terms.
3. Since [tex]\( 2x^3 \)[/tex] grows very large and positive as [tex]\( x \to \infty \)[/tex] (because the coefficient 2 is positive), [tex]\( f(x) \to \infty \)[/tex] as [tex]\( x \to \infty \)[/tex].
### Analyzing as [tex]\( x \to -\infty \)[/tex]:
1. Again, consider the leading term [tex]\( 2x^3 \)[/tex].
2. As [tex]\( x \to -\infty \)[/tex], [tex]\( (-x)^3 = -x^3 \)[/tex] becomes very large and negative.
3. So [tex]\( 2(-x^3) = -2x^3 \)[/tex] also grows very large and negative as [tex]\( x \to -\infty \)[/tex], which means [tex]\( f(x) \to -\infty \)[/tex] as [tex]\( x \to -\infty \)[/tex].
Given these analyses, we conclude:
- As [tex]\( x \to \infty \)[/tex], [tex]\( y \to \infty \)[/tex].
- As [tex]\( x \to -\infty \)[/tex], [tex]\( y \to -\infty \)[/tex].
Therefore, the correct description for the end behavior of the polynomial [tex]\( f(x) = 2x^3 - 26x - 24 \)[/tex] is:
- As [tex]\( x \rightarrow -\infty, y \rightarrow -\infty \)[/tex] and as [tex]\( x \rightarrow \infty, y \rightarrow \infty \)[/tex].
Thus, the answer aligns with the second given option:
- As [tex]\( x \rightarrow -\infty, y \rightarrow -\infty \)[/tex] and as [tex]\( x \rightarrow \infty, y \rightarrow \infty \)[/tex].
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.