Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A 60 cm high cylinder with a 14 cm diameter is cut vertically into two equal halves. What is the volume of one half?

Sagot :

Sure! Let's solve the problem step-by-step.

### Given Information:

1. The height [tex]\( h \)[/tex] of the cylinder is 60 cm.
2. The diameter of the cylinder is 14 cm.
3. When the cylinder is cut vertically, it is divided into two equal halves.

### Step-by-Step Solution:

1. Calculate the radius of the cylinder:
- The radius [tex]\( r \)[/tex] is half of the diameter.
[tex]\[ r = \frac{d}{2} = \frac{14 \, \text{cm}}{2} = 7 \, \text{cm} \][/tex]

2. Calculate the volume of the full cylinder:
- The volume [tex]\( V \)[/tex] of a cylinder is given by the formula:
[tex]\[ V = \pi r^2 h \][/tex]
- Here, [tex]\( r = 7 \, \text{cm} \)[/tex], [tex]\( h = 60 \, \text{cm} \)[/tex], and [tex]\( \pi \approx 3.1416 \)[/tex].

3. Insert the values into the volume formula:
[tex]\[ V = \pi \times (7 \, \text{cm})^2 \times 60 \, \text{cm} \][/tex]

- Squaring the radius:
[tex]\[ r^2 = (7 \, \text{cm})^2 = 49 \, \text{cm}^2 \][/tex]

- Multiplying by the height:
[tex]\[ r^2 \times h = 49 \, \text{cm}^2 \times 60 \, \text{cm} = 2940 \, \text{cm}^3 \][/tex]

- Multiplying by [tex]\( \pi \)[/tex]:
[tex]\[ V = \pi \times 2940 \, \text{cm}^3 \approx 3.1416 \times 2940 \, \text{cm}^3 \approx 9236.282 \, \text{cm}^3 \][/tex]

4. Divide the volume of the full cylinder by 2 to find the volume of one half:
[tex]\[ \text{Volume of one half} = \frac{9236.282 \, \text{cm}^3}{2} \approx 4618.141 \, \text{cm}^3 \][/tex]

### Final Answer:

The volume of one half of the 60 cm high cylinder with a 14 cm diameter, when cut vertically into two equal halves, is approximately 4618.141 cm³.