Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To solve this problem, we will systematically explore the properties of each flask to determine which statement is true:
### Data Given:
- Flask Volume (both flasks): 2.0 L
- Temperature (both flasks): 298 K
- Mass of O2 in Flask A: 16.00 grams
- Mass of N2 in Flask B: 28.0 grams
### Molecular Weights:
- Molar Mass of O2: 32.00 g/mol
- Molar Mass of N2: 28.02 g/mol
### Calculations:
1. Number of Moles:
For Flask A (O2):
[tex]\[ \text{Moles of O2} = \frac{\text{mass}}{\text{molar mass}} = \frac{16.00 \text{ g}}{32.00 \text{ g/mol}} = 0.5 \text{ mol} \][/tex]
For Flask B (N2):
[tex]\[ \text{Moles of N2} = \frac{\text{mass}}{\text{molar mass}} = \frac{28.0 \text{ g}}{28.02 \text{ g/mol}} \approx 1.0 \text{ mol} \][/tex]
2. Using the Ideal Gas Law (PV = nRT):
Where R (gas constant) = 0.0821 L·atm/(mol·K)
For Flask A:
[tex]\[ P_A = \frac{n \cdot R \cdot T}{V} = \frac{0.5 \cdot 0.0821 \cdot 298}{2.0} \approx 6.12 \text{ atm} \][/tex]
For Flask B:
[tex]\[ P_B = \frac{n \cdot R \cdot T}{V} = \frac{1.0 \cdot 0.0821 \cdot 298}{2.0} \approx 12.22 \text{ atm} \][/tex]
3. Density:
Density is calculated as:
[tex]\[ \text{Density} = \frac{\text{mass}}{\text{volume}} \][/tex]
For Flask A:
[tex]\[ \text{Density}_A = \frac{16.00 \text{ g}}{2.0 \text{ L}} = 8.0 \text{ g/L} \][/tex]
For Flask B:
[tex]\[ \text{Density}_B = \frac{28.0 \text{ g}}{2.0 \text{ L}} = 14.0 \text{ g/L} \][/tex]
4. Number of Molecules:
Using Avogadro's number ([tex]\(6.022 \times 10^{23}\)[/tex] molecules/mol):
For Flask A:
[tex]\[ \text{Number of molecules in Flask A} = 0.5 \text{ mol} \times 6.022 \times 10^{23} \approx 3.011 \times 10^{23} \text{ molecules} \][/tex]
For Flask B:
[tex]\[ \text{Number of molecules in Flask B} = 1.0 \text{ mol} \times 6.022 \times 10^{23} \approx 6.0177 \times 10^{23} \text{ molecules} \][/tex]
### Comparison of Statements:
- Statement a: Flask A contains molecules with higher average kinetic energy than Flask B.
- This is false because the average kinetic energy of gas molecules depends on temperature, which is the same for both flasks.
- Statement b: Flask A has a higher density than Flask B.
- This is false because the density of Flask A (8.0 g/L) is less than the density of Flask B (14.0 g/L).
- Statement c: Flask A contains fewer molecules than Flask B.
- This is true because Flask A contains approximately [tex]\(3.011 \times 10^{23}\)[/tex] molecules, which is less than the approximately [tex]\(6.0177 \times 10^{23}\)[/tex] molecules in Flask B.
- Statement d: Flask A has a higher pressure than Flask B.
- This is false because the pressure in Flask A (6.12 atm) is less than the pressure in Flask B (12.22 atm).
### Conclusion:
The correct statement is:
c. Flask A contains fewer molecules than Flask B.
### Data Given:
- Flask Volume (both flasks): 2.0 L
- Temperature (both flasks): 298 K
- Mass of O2 in Flask A: 16.00 grams
- Mass of N2 in Flask B: 28.0 grams
### Molecular Weights:
- Molar Mass of O2: 32.00 g/mol
- Molar Mass of N2: 28.02 g/mol
### Calculations:
1. Number of Moles:
For Flask A (O2):
[tex]\[ \text{Moles of O2} = \frac{\text{mass}}{\text{molar mass}} = \frac{16.00 \text{ g}}{32.00 \text{ g/mol}} = 0.5 \text{ mol} \][/tex]
For Flask B (N2):
[tex]\[ \text{Moles of N2} = \frac{\text{mass}}{\text{molar mass}} = \frac{28.0 \text{ g}}{28.02 \text{ g/mol}} \approx 1.0 \text{ mol} \][/tex]
2. Using the Ideal Gas Law (PV = nRT):
Where R (gas constant) = 0.0821 L·atm/(mol·K)
For Flask A:
[tex]\[ P_A = \frac{n \cdot R \cdot T}{V} = \frac{0.5 \cdot 0.0821 \cdot 298}{2.0} \approx 6.12 \text{ atm} \][/tex]
For Flask B:
[tex]\[ P_B = \frac{n \cdot R \cdot T}{V} = \frac{1.0 \cdot 0.0821 \cdot 298}{2.0} \approx 12.22 \text{ atm} \][/tex]
3. Density:
Density is calculated as:
[tex]\[ \text{Density} = \frac{\text{mass}}{\text{volume}} \][/tex]
For Flask A:
[tex]\[ \text{Density}_A = \frac{16.00 \text{ g}}{2.0 \text{ L}} = 8.0 \text{ g/L} \][/tex]
For Flask B:
[tex]\[ \text{Density}_B = \frac{28.0 \text{ g}}{2.0 \text{ L}} = 14.0 \text{ g/L} \][/tex]
4. Number of Molecules:
Using Avogadro's number ([tex]\(6.022 \times 10^{23}\)[/tex] molecules/mol):
For Flask A:
[tex]\[ \text{Number of molecules in Flask A} = 0.5 \text{ mol} \times 6.022 \times 10^{23} \approx 3.011 \times 10^{23} \text{ molecules} \][/tex]
For Flask B:
[tex]\[ \text{Number of molecules in Flask B} = 1.0 \text{ mol} \times 6.022 \times 10^{23} \approx 6.0177 \times 10^{23} \text{ molecules} \][/tex]
### Comparison of Statements:
- Statement a: Flask A contains molecules with higher average kinetic energy than Flask B.
- This is false because the average kinetic energy of gas molecules depends on temperature, which is the same for both flasks.
- Statement b: Flask A has a higher density than Flask B.
- This is false because the density of Flask A (8.0 g/L) is less than the density of Flask B (14.0 g/L).
- Statement c: Flask A contains fewer molecules than Flask B.
- This is true because Flask A contains approximately [tex]\(3.011 \times 10^{23}\)[/tex] molecules, which is less than the approximately [tex]\(6.0177 \times 10^{23}\)[/tex] molecules in Flask B.
- Statement d: Flask A has a higher pressure than Flask B.
- This is false because the pressure in Flask A (6.12 atm) is less than the pressure in Flask B (12.22 atm).
### Conclusion:
The correct statement is:
c. Flask A contains fewer molecules than Flask B.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.