To solve the problem, follow these steps:
1. Understand the concept: The problem states that the density of glacier ice is about 90% that of fresh water. This means that the volume of water that can be obtained from a certain volume of glacier ice will be 90% of that original glacier volume.
2. Set up the relationship: Let [tex]\( V_g \)[/tex] be the volume of the glacier ice.
3. Calculate the volume of water: To find the volume of water, you need to multiply the volume of the glacier ice by 90% (or 0.9 as a decimal).
[tex]\[ V_w = V_g \times 0.90 \][/tex]
4. Substitute the values and solve:
- If the volume of glacier ice [tex]\( V_g \)[/tex] was given, substitute it here.
- If the problem didn't specify the exact volume, you leave the answer in terms of [tex]\( V_g \)[/tex].
For example, if [tex]\( V_g = 1 \, \text{km}^3 \)[/tex]:
[tex]\[ V_w = 1 \, \text{km}^3 \times 0.90 = 0.90 \, \text{km}^3 \][/tex]
Therefore, given a volume of [tex]\( 1 \, \text{km}^3 \)[/tex] of glacier ice, the corresponding volume of water would be [tex]\( 0.90 \, \text{km}^3 \)[/tex].
Answer:
[tex]\[ 0.90 \, \text{km}^3 \][/tex]
If the specific volume of the glacier ice was not provided in the problem, the formula to use would be:
[tex]\[ V_w = V_g \times 0.90 \][/tex]
So, you need to multiply the volume of glacier ice by 0.90 to obtain the corresponding volume of water in [tex]\( \text{km}^3\)[/tex].
