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The mean ages with standard deviations of four swim teams at a swim club are given below.

\begin{tabular}{|c|c|c|}
\hline Team & Mean & Standard Deviation \\
\hline Stars & 16 & 4.1 \\
\hline Dolphins & 18 & 1.5 \\
\hline Giants & 14 & 0.3 \\
\hline Mackerels & 15 & 2.3 \\
\hline
\end{tabular}

Which statement is most likely to be true?

A. The ages of the Mackerels are the most dispersed from the team's mean.
B. The ages of the Stars are the most dispersed from the team's mean.
C. The ages of the Dolphins are the most dispersed from the team's mean.
D. The ages of the Giants are the most dispersed from the team's mean.

Sagot :

GinnyAnswer
To determine which statement is most likely to be true regarding which team's ages are the most dispersed from the team's mean, we need to compare the standard deviations of the ages for each team. A higher standard deviation indicates greater dispersion of ages around the mean.

Here are the given standard deviations for each team:
- Stars: 4.1
- Dolphins: 1.5
- Giants: 0.3
- Mackerels: 2.3

To find the team with the most dispersed ages, we identify the highest standard deviation among the teams listed.

Comparing the standard deviations:
1. Stars: 4.1
2. Dolphins: 1.5
3. Giants: 0.3
4. Mackerels: 2.3

The highest standard deviation is 4.1, which belongs to the Stars.

Therefore, the statement that is most likely to be true is:
The ages of the Stars are the most dispersed from the team's mean.
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