Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine which equation represents a street parallel to the given line [tex]\( -7x + 3y = -21.5 \)[/tex], we need to follow these steps:
1. Identify the Ratio of the Coefficients:
The equation of the given street [tex]\( -7x + 3y = -21.5 \)[/tex] can be compared to the standard linear form [tex]\( Ax + By = C \)[/tex]. The coefficients of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] are [tex]\( -7 \)[/tex] and [tex]\( 3 \)[/tex], respectively.
2. Calculate the Ratio for the Given Line:
The ratio of the coefficients of [tex]\( x \)[/tex] to [tex]\( y \)[/tex] in the given line is:
[tex]\[ \frac{-7}{3} \][/tex]
3. Determine the Ratios for the Option Lines:
Let's now compare this ratio with the coefficients in the given options:
- Option A: [tex]\( -3x + 4y = 3 \)[/tex]
The coefficients are [tex]\( -3 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 4 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{-3}{4} \][/tex]
- Option B: [tex]\( 3x + 7y = 63 \)[/tex]
The coefficients are [tex]\( 3 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 7 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{3}{7} \][/tex]
- Option C: [tex]\( 2x + y = 20 \)[/tex]
The coefficients are [tex]\( 2 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 1 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{2}{1} \text{ or simply } 2 \][/tex]
- Option D: [tex]\( 7x + 3y = 70 \)[/tex]
The coefficients are [tex]\( 7 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 3 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{7}{3} \][/tex]
4. Compare the Ratios:
We need to compare each of these ratios to the ratio of the given line [tex]\( \frac{-7}{3} \)[/tex]:
- [tex]\( \frac{-3}{4} \neq \frac{-7}{3} \)[/tex]
- [tex]\( \frac{3}{7} \neq \frac{-7}{3} \)[/tex]
- [tex]\( \frac{2}{1} \neq \frac{-7}{3} \)[/tex]
- [tex]\( \frac{7}{3} \)[/tex] matches the negative of [tex]\( \frac{-7}{3} \)[/tex]. Moreover, [tex]\( \frac{7}{3} \)[/tex] is the positive version which signifies parallelism, as parallel lines have the same gradient (magnitude of the ratio) even if they differ in sign.
5. Conclusion:
The equation of the line parallel to the given line [tex]\( -7x + 3y = -21.5 \)[/tex] is:
[tex]\[ \boxed{7x + 3y = 70} \][/tex]
Option D correctly represents the equation of the central street [tex]\( PQ \)[/tex].
1. Identify the Ratio of the Coefficients:
The equation of the given street [tex]\( -7x + 3y = -21.5 \)[/tex] can be compared to the standard linear form [tex]\( Ax + By = C \)[/tex]. The coefficients of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] are [tex]\( -7 \)[/tex] and [tex]\( 3 \)[/tex], respectively.
2. Calculate the Ratio for the Given Line:
The ratio of the coefficients of [tex]\( x \)[/tex] to [tex]\( y \)[/tex] in the given line is:
[tex]\[ \frac{-7}{3} \][/tex]
3. Determine the Ratios for the Option Lines:
Let's now compare this ratio with the coefficients in the given options:
- Option A: [tex]\( -3x + 4y = 3 \)[/tex]
The coefficients are [tex]\( -3 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 4 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{-3}{4} \][/tex]
- Option B: [tex]\( 3x + 7y = 63 \)[/tex]
The coefficients are [tex]\( 3 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 7 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{3}{7} \][/tex]
- Option C: [tex]\( 2x + y = 20 \)[/tex]
The coefficients are [tex]\( 2 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 1 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{2}{1} \text{ or simply } 2 \][/tex]
- Option D: [tex]\( 7x + 3y = 70 \)[/tex]
The coefficients are [tex]\( 7 \)[/tex] for [tex]\( x \)[/tex] and [tex]\( 3 \)[/tex] for [tex]\( y \)[/tex]. The ratio is:
[tex]\[ \frac{7}{3} \][/tex]
4. Compare the Ratios:
We need to compare each of these ratios to the ratio of the given line [tex]\( \frac{-7}{3} \)[/tex]:
- [tex]\( \frac{-3}{4} \neq \frac{-7}{3} \)[/tex]
- [tex]\( \frac{3}{7} \neq \frac{-7}{3} \)[/tex]
- [tex]\( \frac{2}{1} \neq \frac{-7}{3} \)[/tex]
- [tex]\( \frac{7}{3} \)[/tex] matches the negative of [tex]\( \frac{-7}{3} \)[/tex]. Moreover, [tex]\( \frac{7}{3} \)[/tex] is the positive version which signifies parallelism, as parallel lines have the same gradient (magnitude of the ratio) even if they differ in sign.
5. Conclusion:
The equation of the line parallel to the given line [tex]\( -7x + 3y = -21.5 \)[/tex] is:
[tex]\[ \boxed{7x + 3y = 70} \][/tex]
Option D correctly represents the equation of the central street [tex]\( PQ \)[/tex].
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.