Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To solve the problem and determine which expression is missing from step 7, we will use the Pythagorean theorem applied to right triangle [tex]\(\triangle ABC\)[/tex].
Given:
- [tex]\(\angle ABC\)[/tex] is a right angle, indicating [tex]\( \triangle ABC \)[/tex] is a right triangle.
- The side lengths are given by:
- [tex]\( BA = \sqrt{1 + d^2} \)[/tex]
- [tex]\( BC = \sqrt{e^2 + 1} \)[/tex]
- [tex]\( CA = \sqrt{(d - e)^2} = d - e \)[/tex]
The Pythagorean theorem states:
[tex]\[ AB^2 + BC^2 = AC^2 \][/tex]
So, let’s substitute the given side lengths into the Pythagorean theorem:
1. Calculate [tex]\(AB^2\)[/tex]:
[tex]\[ AB^2 = \left( \sqrt{1 + d^2} \right)^2 = 1 + d^2 \][/tex]
2. Calculate [tex]\(BC^2\)[/tex]:
[tex]\[ BC^2 = \left( \sqrt{e^2 + 1} \right)^2 = e^2 + 1 \][/tex]
3. Calculate [tex]\(AC^2\)[/tex]:
[tex]\[ AC^2 = \left( \sqrt{(d - e)^2} \right)^2 = (d - e)^2 \][/tex]
According to the Pythagorean theorem:
[tex]\[ AB^2 + BC^2 = AC^2 \][/tex]
Substitute the values we computed:
[tex]\[ (1 + d^2) + (e^2 + 1) = (d - e)^2 \][/tex]
Simplify the left-hand side:
[tex]\[ 2 + d^2 + e^2 = (d - e)^2 \][/tex]
Now, expand the right-hand side:
[tex]\[ (d - e)^2 = d^2 - 2de + e^2 \][/tex]
Thus, we have:
[tex]\[ 2 + d^2 + e^2 = d^2 - 2de + e^2 \][/tex]
Comparing both sides, we see that the equation:
[tex]\[ 2 + d^2 + e^2 = d^2 - 2de + e^2 \][/tex]
Clearly, the expression [tex]\((d - e)^2\)[/tex] from option C matches what we need on the right-hand side of the equation.
Therefore, the missing expression is:
[tex]\[ (d - e)^2 \][/tex]
So, the correct option is C. [tex]\( (d - e)^2 \)[/tex].
Given:
- [tex]\(\angle ABC\)[/tex] is a right angle, indicating [tex]\( \triangle ABC \)[/tex] is a right triangle.
- The side lengths are given by:
- [tex]\( BA = \sqrt{1 + d^2} \)[/tex]
- [tex]\( BC = \sqrt{e^2 + 1} \)[/tex]
- [tex]\( CA = \sqrt{(d - e)^2} = d - e \)[/tex]
The Pythagorean theorem states:
[tex]\[ AB^2 + BC^2 = AC^2 \][/tex]
So, let’s substitute the given side lengths into the Pythagorean theorem:
1. Calculate [tex]\(AB^2\)[/tex]:
[tex]\[ AB^2 = \left( \sqrt{1 + d^2} \right)^2 = 1 + d^2 \][/tex]
2. Calculate [tex]\(BC^2\)[/tex]:
[tex]\[ BC^2 = \left( \sqrt{e^2 + 1} \right)^2 = e^2 + 1 \][/tex]
3. Calculate [tex]\(AC^2\)[/tex]:
[tex]\[ AC^2 = \left( \sqrt{(d - e)^2} \right)^2 = (d - e)^2 \][/tex]
According to the Pythagorean theorem:
[tex]\[ AB^2 + BC^2 = AC^2 \][/tex]
Substitute the values we computed:
[tex]\[ (1 + d^2) + (e^2 + 1) = (d - e)^2 \][/tex]
Simplify the left-hand side:
[tex]\[ 2 + d^2 + e^2 = (d - e)^2 \][/tex]
Now, expand the right-hand side:
[tex]\[ (d - e)^2 = d^2 - 2de + e^2 \][/tex]
Thus, we have:
[tex]\[ 2 + d^2 + e^2 = d^2 - 2de + e^2 \][/tex]
Comparing both sides, we see that the equation:
[tex]\[ 2 + d^2 + e^2 = d^2 - 2de + e^2 \][/tex]
Clearly, the expression [tex]\((d - e)^2\)[/tex] from option C matches what we need on the right-hand side of the equation.
Therefore, the missing expression is:
[tex]\[ (d - e)^2 \][/tex]
So, the correct option is C. [tex]\( (d - e)^2 \)[/tex].
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.