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Sagot :
Certainly! Let's examine the given quadratic equation:
[tex]\[ 9x^2 - x + 9 = 0 \][/tex]
In this equation, we can identify the coefficients of [tex]\( x^2 \)[/tex], [tex]\( x \)[/tex], and the constant term to place it in the standard quadratic form [tex]\( ax^2 + bx + c = 0 \)[/tex].
In the standard quadratic form [tex]\( ax^2 + bx + c = 0 \)[/tex]:
- [tex]\( a \)[/tex] represents the coefficient of [tex]\( x^2 \)[/tex]
- [tex]\( b \)[/tex] represents the coefficient of [tex]\( x \)[/tex]
- [tex]\( c \)[/tex] represents the constant term
For the given equation [tex]\( 9x^2 - x + 9 = 0 \)[/tex]:
- The coefficient of [tex]\( x^2 \)[/tex] is [tex]\( 9 \)[/tex]
- The coefficient of [tex]\( x \)[/tex] is [tex]\( -1 \)[/tex]
- The constant term is [tex]\( 9 \)[/tex]
Thus, the value of [tex]\( a \)[/tex] here is:
[tex]\[ a = 9 \][/tex]
So, [tex]\( a \)[/tex] is [tex]\( 9 \)[/tex].
[tex]\[ 9x^2 - x + 9 = 0 \][/tex]
In this equation, we can identify the coefficients of [tex]\( x^2 \)[/tex], [tex]\( x \)[/tex], and the constant term to place it in the standard quadratic form [tex]\( ax^2 + bx + c = 0 \)[/tex].
In the standard quadratic form [tex]\( ax^2 + bx + c = 0 \)[/tex]:
- [tex]\( a \)[/tex] represents the coefficient of [tex]\( x^2 \)[/tex]
- [tex]\( b \)[/tex] represents the coefficient of [tex]\( x \)[/tex]
- [tex]\( c \)[/tex] represents the constant term
For the given equation [tex]\( 9x^2 - x + 9 = 0 \)[/tex]:
- The coefficient of [tex]\( x^2 \)[/tex] is [tex]\( 9 \)[/tex]
- The coefficient of [tex]\( x \)[/tex] is [tex]\( -1 \)[/tex]
- The constant term is [tex]\( 9 \)[/tex]
Thus, the value of [tex]\( a \)[/tex] here is:
[tex]\[ a = 9 \][/tex]
So, [tex]\( a \)[/tex] is [tex]\( 9 \)[/tex].
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