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Part 3 of 4

[tex]\[ 9x^2 - x + 9 = 0 \][/tex]

This equation is in the form [tex]\[ax^2 + bx + c = 0\][/tex], where [tex]\[b = \square\][/tex].

Sagot :

GinnyAnswer
The given equation is [tex]\( 9x^2 - x + 9 = 0 \)[/tex].

This equation is a quadratic equation in the standard form [tex]\( ax^2 + bx + c = 0 \)[/tex].

To identify the coefficient [tex]\( b \)[/tex], let's match the given equation with the standard form:

1. Identify the coefficient of [tex]\( x^2 \)[/tex]:
- In the given equation [tex]\( 9x^2 - x + 9 = 0 \)[/tex], the coefficient of [tex]\( x^2 \)[/tex] is 9. So, [tex]\( a = 9 \)[/tex].

2. Identify the coefficient of [tex]\( x \)[/tex]:
- In the given equation [tex]\( 9x^2 - x + 9 = 0 \)[/tex], the coefficient of [tex]\( x \)[/tex] is -1. So, [tex]\( b = -1 \)[/tex].

3. Identify the constant term (the coefficient of [tex]\( x^0 \)[/tex]):
- In the given equation [tex]\( 9x^2 - x + 9 = 0 \)[/tex], the constant term is 9. So, [tex]\( c = 9 \)[/tex].

Therefore, the coefficient [tex]\( b \)[/tex] in the equation [tex]\( 9x^2 - x + 9 = 0 \)[/tex] is [tex]\( -1 \)[/tex].

So, [tex]\( b = -1 \)[/tex].
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