Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
To determine the best seating section for Leanne's family to maximize their chances of having a "perfect" view of the symphony's soloist, we need to analyze the data given for each section. The relevant data includes the number of reviewers in each section and the number of those reviewers who rated the view as "perfect."
Here is the data presented:
[tex]\[ \begin{array}{|c|c|c|} \hline \text{Section} & \text{Number of Reviewers} & \text{Number of Perfect Ratings} \\ \hline L1 & 90 & 57 \\ \hline L2 & 52 & 33 \\ \hline L3 & 75 & 47 \\ \hline U1 & 84 & 55 \\ \hline U2 & 43 & 27 \\ \hline U3 & 35 & 22 \\ \hline \end{array} \][/tex]
To find out which section has the highest chances of giving a "perfect" view, we need to calculate the ratio of "perfect" reviews to the total number of reviewers for each section. This ratio can be found using the following formula:
[tex]\[ \text{Ratio} = \frac{\text{Number of Perfect Ratings}}{\text{Number of Reviewers}} \][/tex]
Let's calculate the ratio for each section:
Section L1:
[tex]\[ \text{Ratio} = \frac{57}{90} \approx 0.6333 \][/tex]
Section L2:
[tex]\[ \text{Ratio} = \frac{33}{52} \approx 0.6346 \][/tex]
Section L3:
[tex]\[ \text{Ratio} = \frac{47}{75} \approx 0.6267 \][/tex]
Section U1:
[tex]\[ \text{Ratio} = \frac{55}{84} \approx 0.6548 \][/tex]
Section U2:
[tex]\[ \text{Ratio} = \frac{27}{43} \approx 0.6279 \][/tex]
Section U3:
[tex]\[ \text{Ratio} = \frac{22}{35} \approx 0.6286 \][/tex]
Now, let's compare these ratios:
- L1: [tex]\(0.6333\)[/tex]
- L2: [tex]\(0.6346\)[/tex]
- L3: [tex]\(0.6267\)[/tex]
- U1: [tex]\(0.6548\)[/tex]
- U2: [tex]\(0.6279\)[/tex]
- U3: [tex]\(0.6286\)[/tex]
We observe that Section U1 has the highest ratio of [tex]\(0.6548\)[/tex].
Therefore, Leanne's family should book their tickets in Section U1 to maximize their chances of having a "perfect" view of the symphony's soloist.
Here is the data presented:
[tex]\[ \begin{array}{|c|c|c|} \hline \text{Section} & \text{Number of Reviewers} & \text{Number of Perfect Ratings} \\ \hline L1 & 90 & 57 \\ \hline L2 & 52 & 33 \\ \hline L3 & 75 & 47 \\ \hline U1 & 84 & 55 \\ \hline U2 & 43 & 27 \\ \hline U3 & 35 & 22 \\ \hline \end{array} \][/tex]
To find out which section has the highest chances of giving a "perfect" view, we need to calculate the ratio of "perfect" reviews to the total number of reviewers for each section. This ratio can be found using the following formula:
[tex]\[ \text{Ratio} = \frac{\text{Number of Perfect Ratings}}{\text{Number of Reviewers}} \][/tex]
Let's calculate the ratio for each section:
Section L1:
[tex]\[ \text{Ratio} = \frac{57}{90} \approx 0.6333 \][/tex]
Section L2:
[tex]\[ \text{Ratio} = \frac{33}{52} \approx 0.6346 \][/tex]
Section L3:
[tex]\[ \text{Ratio} = \frac{47}{75} \approx 0.6267 \][/tex]
Section U1:
[tex]\[ \text{Ratio} = \frac{55}{84} \approx 0.6548 \][/tex]
Section U2:
[tex]\[ \text{Ratio} = \frac{27}{43} \approx 0.6279 \][/tex]
Section U3:
[tex]\[ \text{Ratio} = \frac{22}{35} \approx 0.6286 \][/tex]
Now, let's compare these ratios:
- L1: [tex]\(0.6333\)[/tex]
- L2: [tex]\(0.6346\)[/tex]
- L3: [tex]\(0.6267\)[/tex]
- U1: [tex]\(0.6548\)[/tex]
- U2: [tex]\(0.6279\)[/tex]
- U3: [tex]\(0.6286\)[/tex]
We observe that Section U1 has the highest ratio of [tex]\(0.6548\)[/tex].
Therefore, Leanne's family should book their tickets in Section U1 to maximize their chances of having a "perfect" view of the symphony's soloist.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.