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If [tex]$A^2 + B^2 = A^2 + X^2$[/tex], then [tex]$B$[/tex] equals:

A. [tex]\pm X[/tex]
B. [tex]x^2 - 2 A^2[/tex]
C. [tex]\pm A[/tex]
D. [tex]A^2 + X^2[/tex]


Sagot :

Let’s solve the equation step-by-step.

We are given the equation:
[tex]\[ A^2 + B^2 = A^2 + X^2 \][/tex]

To find [tex]\(B\)[/tex], follow these steps:

1. Subtract [tex]\(A^2\)[/tex] from both sides:
[tex]\[ A^2 + B^2 - A^2 = A^2 + X^2 - A^2 \][/tex]
This simplifies to:
[tex]\[ B^2 = X^2 \][/tex]

2. Take the square root of both sides:
[tex]\[ \sqrt{B^2} = \sqrt{X^2} \][/tex]

Since the square root of [tex]\(B^2\)[/tex] is the absolute value of [tex]\(B\)[/tex], and the square root of [tex]\(X^2\)[/tex] is the absolute value of [tex]\(X\)[/tex], we have:
[tex]\[ |B| = |X| \][/tex]

3. Consider the possible values:
The absolute value equation [tex]\(|B| = |X|\)[/tex] implies that [tex]\(B\)[/tex] can be either [tex]\(X\)[/tex] or [tex]\(-X\)[/tex]:
[tex]\[ B = X \quad \text{or} \quad B = -X \][/tex]

Thus, [tex]\(B\)[/tex] can be [tex]\(\pm X\)[/tex].

Therefore, the correct answer is:

[tex]\[ \text{a) } \pm X \][/tex]