Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

If a force of 10 N produces an acceleration of [tex]$2 \, \text{ms}^{-2}$[/tex] in a body of mass [tex]m_1[/tex] and [tex]5 \, \text{ms}^{-2}$[/tex] in a body of mass [tex]m_2[/tex], what will be the acceleration produced by the same force when both bodies are tied together?

Ans. [tex]$1.43 \, \text{ms}^{-2}$[/tex]


Sagot :

Certainly! Let's solve this problem step by step.

1. Identify the given data:
- Force, [tex]\( F = 10 \, \text{N} \)[/tex]
- Acceleration of body [tex]\( m_1 \)[/tex], [tex]\( a_1 = 2 \, \text{m/s}^2 \)[/tex]
- Acceleration of body [tex]\( m_2 \)[/tex], [tex]\( a_2 = 5 \, \text{m/s}^2 \)[/tex]

2. Determine the masses [tex]\( m_1 \)[/tex] and [tex]\( m_2 \)[/tex]:
Using the formula [tex]\( F = m \cdot a \)[/tex]
- For body [tex]\( m_1 \)[/tex]:
[tex]\[ F = m_1 \cdot a_1 \][/tex]
[tex]\[ m_1 = \frac{F}{a_1} = \frac{10 \, \text{N}}{2 \, \text{m/s}^2} = 5 \, \text{kg} \][/tex]

- For body [tex]\( m_2 \)[/tex]:
[tex]\[ F = m_2 \cdot a_2 \][/tex]
[tex]\[ m_2 = \frac{F}{a_2} = \frac{10 \, \text{N}}{5 \, \text{m/s}^2} = 2 \, \text{kg} \][/tex]

3. Calculate the total mass when both bodies are tied together:
[tex]\[ \text{Total mass} = m_1 + m_2 = 5 \, \text{kg} + 2 \, \text{kg} = 7 \, \text{kg} \][/tex]

4. Determine the acceleration for the combined mass using the same force:
Using the formula [tex]\( F = m \cdot a \)[/tex] again, for the total mass:
[tex]\[ F = \text{Total mass} \cdot \text{Total acceleration} \][/tex]
[tex]\[ 10 \, \text{N} = 7 \, \text{kg} \cdot a \][/tex]
[tex]\[ a = \frac{10 \, \text{N}}{7 \, \text{kg}} \approx 1.4286 \, \text{m/s}^2 \][/tex]

Therefore, the acceleration produced by the same force when both bodies are tied together is approximately [tex]\( 1.43 \, \text{m/s}^2 \)[/tex].