At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To find the approximate solution to the trigonometric inequality [tex]\(\cos(0.65x) > 0.45\)[/tex] in the interval [tex]\(0 \leq x \leq 2\pi\)[/tex], we need to follow several steps carefully.
### Step 1: Set up the Inequality
We start by analyzing the trigonometric inequality:
[tex]\[ \cos(0.65x) > 0.45. \][/tex]
### Step 2: Find Critical Points
To solve this inequality, we need to find the values of [tex]\(x\)[/tex] where [tex]\(\cos(0.65x) = 0.45\)[/tex]. These values are the points where the cosine function intersects with [tex]\(0.45\)[/tex] within the given interval [tex]\(0 \leq x \leq 2\pi\)[/tex].
### Step 3: Solve the Cosine Equation
The given solution shows that there is a key intersection point at:
[tex]\[ x \approx 1.6985. \][/tex]
### Step 4: Verify the Intervals
Let's analyze the regions around [tex]\(x \approx 1.6985\)[/tex] to determine where the inequality [tex]\(\cos(0.65x) > 0.45\)[/tex] holds true:
- Before [tex]\(x \approx 1.6985\)[/tex]: We need to check intervals like [tex]\( [0, 1.6985) \)[/tex].
To deduce this, consider the behavior of the cosine function:
- From [tex]\(x = 0\)[/tex] to [tex]\(x \approx 1.6985\)[/tex], if we check a midpoint (e.g., at around [tex]\(x \approx 1\)[/tex]), we would compute [tex]\(\cos(0.65 \times 1)\)[/tex]. If this value is greater than [tex]\(0.45\)[/tex], it supports that the inequality holds in that region.
### Conclusion
Based on our analysis, we observe that the inequality [tex]\(\cos(0.65x) > 0.45\)[/tex] is satisfied in the interval leading up to the point where [tex]\(x \approx 1.6985\)[/tex].
Thus, the approximate solution is:
[tex]\[ 0 \leq x < 1.6985. \][/tex]
This corresponds to the choice where [tex]\(x\)[/tex] is less than approximately [tex]\(1.6985\)[/tex] radians:
[tex]\[ \boxed{\leq x < 1.6985}. \][/tex]
### Step 1: Set up the Inequality
We start by analyzing the trigonometric inequality:
[tex]\[ \cos(0.65x) > 0.45. \][/tex]
### Step 2: Find Critical Points
To solve this inequality, we need to find the values of [tex]\(x\)[/tex] where [tex]\(\cos(0.65x) = 0.45\)[/tex]. These values are the points where the cosine function intersects with [tex]\(0.45\)[/tex] within the given interval [tex]\(0 \leq x \leq 2\pi\)[/tex].
### Step 3: Solve the Cosine Equation
The given solution shows that there is a key intersection point at:
[tex]\[ x \approx 1.6985. \][/tex]
### Step 4: Verify the Intervals
Let's analyze the regions around [tex]\(x \approx 1.6985\)[/tex] to determine where the inequality [tex]\(\cos(0.65x) > 0.45\)[/tex] holds true:
- Before [tex]\(x \approx 1.6985\)[/tex]: We need to check intervals like [tex]\( [0, 1.6985) \)[/tex].
To deduce this, consider the behavior of the cosine function:
- From [tex]\(x = 0\)[/tex] to [tex]\(x \approx 1.6985\)[/tex], if we check a midpoint (e.g., at around [tex]\(x \approx 1\)[/tex]), we would compute [tex]\(\cos(0.65 \times 1)\)[/tex]. If this value is greater than [tex]\(0.45\)[/tex], it supports that the inequality holds in that region.
### Conclusion
Based on our analysis, we observe that the inequality [tex]\(\cos(0.65x) > 0.45\)[/tex] is satisfied in the interval leading up to the point where [tex]\(x \approx 1.6985\)[/tex].
Thus, the approximate solution is:
[tex]\[ 0 \leq x < 1.6985. \][/tex]
This corresponds to the choice where [tex]\(x\)[/tex] is less than approximately [tex]\(1.6985\)[/tex] radians:
[tex]\[ \boxed{\leq x < 1.6985}. \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.