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लगाडनुहांस ।

In a continuous series, the mean [tex]\((\bar{X}) = 19 + 2m\)[/tex] and [tex]\(\Sigma fx = 133 + 14m\)[/tex]. Find the number of terms.


Sagot :

स्कन्धात्मक श्रेणीमा, हामीलाई यसको माध्य र [tex]$\Sigma fx$[/tex] को मान दिइएको छ। यस स्थितिमा दीएका मानहरू:

माध्य ( [tex]$\bar{X}$[/tex] ) = [tex]\(19 + 2\)[/tex]

सङ्कलनीय निष्कर्ष: [tex]$\Sigma fx$[/tex] = [tex]\(133 + 14\)[/tex]

पहिलो चरणमा, हामी माध्यको मान गणना गर्छौं:

[tex]\[ \bar{X} = 19 + 2 = 21 \][/tex]

दोस्रो चरणमा, हामी [tex]$\Sigma fx$[/tex] को मान गणना गर्छौं:

[tex]\[ \Sigma fx = 133 + 14 = 147 \][/tex]

अन्ततः, स्कन्धात्मक श्रेणीमा [tex]\(N\)[/tex] को मान निकाल्न आत प्रकल्पन गर्न सकिन्छ:

संख्या पदहरूको ( [tex]\(N\)[/tex] ) ना गणना यस सूत्रबाट मिलाईन्छ:

[tex]\[ N = \frac{\Sigma fx}{\bar{X}} \][/tex]

तीस्रो चरणमा, हामी [tex]\(N\)[/tex] को मान निकाल्न यस सूत्र प्रयोग गर्छौं:

[tex]\[ N = \frac{147}{21} = 7 \][/tex]

त्यसर्थ, स्कन्धात्मक श्रेणीमा संख्या पदहरूको संख्या [tex]\(N = 7\)[/tex] हुन्छ।

सारांशमा, माध्य, [tex]$\Sigma fx$[/tex], र पदहरूको संख्या ठहरिअनुसार:

माध्य = 21

[tex]$\Sigma fx$[/tex] = 147

पदहरूको संख्या ( [tex]\(N\)[/tex] ) = 7
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