Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
We are given two products and we need to subtract one from the other. First, let's compute each of these products step-by-step.
### Step 1: Compute the product of terms [tex]\(\left(\frac{4}{3} l^2 m n\right), \left(-5 l m n^2\right)\)[/tex], and [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]
1. Multiply [tex]\(\left(\frac{4}{3} l^2 m n\right)\)[/tex] and [tex]\(\left(-5 l m n^2\right)\)[/tex]:
[tex]\[ \left(\frac{4}{3} l^2 m n\right) \cdot \left(-5 l m n^2\right) = \left(\frac{4}{3} \cdot -5\right) \cdot l^2 \cdot l \cdot m \cdot m \cdot n \cdot n^2 \][/tex]
[tex]\[ = \left(-\frac{20}{3}\right) \cdot l^3 \cdot m^2 \cdot n^3 \][/tex]
2. Now, multiply the result by [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]:
[tex]\[ \left(-\frac{20}{3} l^3 m^2 n^3\right) \cdot \left(\frac{1}{3} l^2 m n\right) = \left(-\frac{20}{3} \cdot \frac{1}{3}\right) \cdot l^3 \cdot l^2 \cdot m^2 \cdot m \cdot n^3 \cdot n \][/tex]
[tex]\[ = \left(-\frac{20}{9}\right) \cdot l^{5} \cdot m^{3} \cdot n^{4} \][/tex]
### Step 2: Compute the product of terms [tex]\(\left(\frac{7}{3} l^3 m n^2\right)\)[/tex] and [tex]\(\left(\frac{2}{3} l^2 m^2 n^2\right)\)[/tex]
1. Multiply the terms directly:
[tex]\[ \left(\frac{7}{3} l^3 m n^2\right) \cdot \left(\frac{2}{3} l^2 m^2 n^2\right) = \left(\frac{7}{3} \cdot \frac{2}{3}\right) \cdot l^3 \cdot l^2 \cdot m \cdot m^2 \cdot n^2 \cdot n^2 \][/tex]
[tex]\[ = \left(\frac{14}{9}\right) \cdot l^5 \cdot m^3 \cdot n^4 \][/tex]
### Step 3: Subtract the second product from the first product
[tex]\[ \left(-\frac{20}{9} l^{5} m^{3} n^{4}\right) - \left(\frac{14}{9} l^{5} m^{3} n^{4}\right) = \frac{-20 - 14}{9} l^{5} m^{3} n^{4} = \frac{-34}{9} l^{5} m^{3} n^{4} \][/tex]
Thus, the final result after subtracting the second product from the first is:
[tex]\[ \boxed{-\frac{34}{9} l^5 m^3 n^4} \][/tex]
### Step 1: Compute the product of terms [tex]\(\left(\frac{4}{3} l^2 m n\right), \left(-5 l m n^2\right)\)[/tex], and [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]
1. Multiply [tex]\(\left(\frac{4}{3} l^2 m n\right)\)[/tex] and [tex]\(\left(-5 l m n^2\right)\)[/tex]:
[tex]\[ \left(\frac{4}{3} l^2 m n\right) \cdot \left(-5 l m n^2\right) = \left(\frac{4}{3} \cdot -5\right) \cdot l^2 \cdot l \cdot m \cdot m \cdot n \cdot n^2 \][/tex]
[tex]\[ = \left(-\frac{20}{3}\right) \cdot l^3 \cdot m^2 \cdot n^3 \][/tex]
2. Now, multiply the result by [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]:
[tex]\[ \left(-\frac{20}{3} l^3 m^2 n^3\right) \cdot \left(\frac{1}{3} l^2 m n\right) = \left(-\frac{20}{3} \cdot \frac{1}{3}\right) \cdot l^3 \cdot l^2 \cdot m^2 \cdot m \cdot n^3 \cdot n \][/tex]
[tex]\[ = \left(-\frac{20}{9}\right) \cdot l^{5} \cdot m^{3} \cdot n^{4} \][/tex]
### Step 2: Compute the product of terms [tex]\(\left(\frac{7}{3} l^3 m n^2\right)\)[/tex] and [tex]\(\left(\frac{2}{3} l^2 m^2 n^2\right)\)[/tex]
1. Multiply the terms directly:
[tex]\[ \left(\frac{7}{3} l^3 m n^2\right) \cdot \left(\frac{2}{3} l^2 m^2 n^2\right) = \left(\frac{7}{3} \cdot \frac{2}{3}\right) \cdot l^3 \cdot l^2 \cdot m \cdot m^2 \cdot n^2 \cdot n^2 \][/tex]
[tex]\[ = \left(\frac{14}{9}\right) \cdot l^5 \cdot m^3 \cdot n^4 \][/tex]
### Step 3: Subtract the second product from the first product
[tex]\[ \left(-\frac{20}{9} l^{5} m^{3} n^{4}\right) - \left(\frac{14}{9} l^{5} m^{3} n^{4}\right) = \frac{-20 - 14}{9} l^{5} m^{3} n^{4} = \frac{-34}{9} l^{5} m^{3} n^{4} \][/tex]
Thus, the final result after subtracting the second product from the first is:
[tex]\[ \boxed{-\frac{34}{9} l^5 m^3 n^4} \][/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.