Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine the correct equations for this scenario, let’s break down the information given:
1. You want to buy a total of 6 potted rose plants.
2. The plants in 8-inch pots cost [tex]$12 each. 3. The plants in 10-inch pots cost $[/tex]15 each.
4. You spend a total of $78.
Let:
- [tex]\( x \)[/tex] be the number of 8-inch pots.
- [tex]\( y \)[/tex] be the number of 10-inch pots.
### Step-by-Step Solution:
1. Equating the total number of pots:
You are purchasing a total of 6 plants which gives us the equation:
[tex]\[ x + y = 6 \][/tex]
2. Equating the total cost:
The total cost is the sum of the cost of 8-inch pots and the cost of 10-inch pots. Therefore, the equation for the total cost is:
[tex]\[ 12x + 15y = 78 \][/tex]
### Given Options:
1. [tex]\( x + y = 78 \)[/tex] and [tex]\( 12x + 15y = 6(78) \)[/tex]
2. [tex]\( y + 15y = 6 \)[/tex]
3. [tex]\( 12x + x = 78 \)[/tex]
4. [tex]\( x + y = 6 \)[/tex] and [tex]\( 12x + 15y = 78 \)[/tex]
5. [tex]\( x + y = 6 \)[/tex] and [tex]\( 15x + 12y = 78 \)[/tex]
### Explanation of Each Option:
- Option 1: Incorrect because [tex]\( x + y = 78 \)[/tex] is not the correct equation for the number of pots.
- Option 2: Incorrect because [tex]\( y + 15y = 6 \)[/tex] does not make logical sense.
- Option 3: Incorrect because [tex]\( 12x + x = 78 \)[/tex] is not relevant to the problem.
- Option 4: Correct, as it matches both correct equations derived from the given information.
- Option 5: Incorrect because the cost equation [tex]\( 15x + 12y = 78 \)[/tex] has the coefficients swapped.
### Conclusion:
The correct set of equations representing this scenario is:
[tex]\[ \begin{array}{l} x + y = 6 \\ 12x + 15y = 78 \end{array} \][/tex]
Thus, the correct choice is:
[tex]\[ \boxed{4} \][/tex]
1. You want to buy a total of 6 potted rose plants.
2. The plants in 8-inch pots cost [tex]$12 each. 3. The plants in 10-inch pots cost $[/tex]15 each.
4. You spend a total of $78.
Let:
- [tex]\( x \)[/tex] be the number of 8-inch pots.
- [tex]\( y \)[/tex] be the number of 10-inch pots.
### Step-by-Step Solution:
1. Equating the total number of pots:
You are purchasing a total of 6 plants which gives us the equation:
[tex]\[ x + y = 6 \][/tex]
2. Equating the total cost:
The total cost is the sum of the cost of 8-inch pots and the cost of 10-inch pots. Therefore, the equation for the total cost is:
[tex]\[ 12x + 15y = 78 \][/tex]
### Given Options:
1. [tex]\( x + y = 78 \)[/tex] and [tex]\( 12x + 15y = 6(78) \)[/tex]
2. [tex]\( y + 15y = 6 \)[/tex]
3. [tex]\( 12x + x = 78 \)[/tex]
4. [tex]\( x + y = 6 \)[/tex] and [tex]\( 12x + 15y = 78 \)[/tex]
5. [tex]\( x + y = 6 \)[/tex] and [tex]\( 15x + 12y = 78 \)[/tex]
### Explanation of Each Option:
- Option 1: Incorrect because [tex]\( x + y = 78 \)[/tex] is not the correct equation for the number of pots.
- Option 2: Incorrect because [tex]\( y + 15y = 6 \)[/tex] does not make logical sense.
- Option 3: Incorrect because [tex]\( 12x + x = 78 \)[/tex] is not relevant to the problem.
- Option 4: Correct, as it matches both correct equations derived from the given information.
- Option 5: Incorrect because the cost equation [tex]\( 15x + 12y = 78 \)[/tex] has the coefficients swapped.
### Conclusion:
The correct set of equations representing this scenario is:
[tex]\[ \begin{array}{l} x + y = 6 \\ 12x + 15y = 78 \end{array} \][/tex]
Thus, the correct choice is:
[tex]\[ \boxed{4} \][/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.