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What will be the output for the following program segment?

```java
int a = 0, b = 10, c = 40;
a = --b + c + ++b;

System.out.println("a = " + a);
```

Sagot :

GinnyAnswer
Alright, let's break down the given program segment step by step to find the value of `a`.

### Initial Values
- [tex]\( a = 0 \)[/tex]
- [tex]\( b = 10 \)[/tex]
- [tex]\( c = 40 \)[/tex]

### Step-by-Step Execution

1. Pre-decrement `b`:
- The `--b` operation decrements `b` by 1 before it is used in the expression.
- After `--b`, the value of `b` becomes:
[tex]\[ b = b - 1 = 10 - 1 = 9 \][/tex]
- So, `--b` results in 9.

2. Value of `c`:
- The value of `c` remains unchanged and is directly used in the expression.
[tex]\[ c = 40 \][/tex]

3. Pre-increment `b`:
- The `++b` operation increments `b` by 1 before it is used in the expression.
- After `++b`, the value of `b` becomes:
[tex]\[ b = b + 1 = 9 + 1 = 10 \][/tex]
- So, `++b` results in 10.

### Combining All the Parts
- Now combine the values from the operations:
[tex]\[ a = (--b) + c + (++b) = 9 + 40 + 10 \][/tex]

### Calculating the Value of `a`
- Adding up the values:
[tex]\[ a = 9 + 40 + 10 = 59 \][/tex]

### Final Values
- After executing the program segment, the values are:
[tex]\[ a = 59, \quad b = 10, \quad c = 40 \][/tex]

### Output
- The output of the print statement will display:
[tex]\[ a = 59 \][/tex]

Thus, the output of the given program segment is: `a = 59`.
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