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Write [tex]$3 \ln 2 + 2 \ln 3$[/tex] as a single logarithm.

A. [tex]\ln 72[/tex]
B. [tex]\ln 12[/tex]

Sagot :

To express [tex]\( 3 \ln 2 + 2 \ln 3 \)[/tex] as a single logarithm, we can utilize properties of logarithms, specifically the power rule and product rule.

1. Power Rule: The power rule states that [tex]\( a \ln(x) = \ln(x^a) \)[/tex]. Let's apply this rule to each term in the expression:
[tex]\[ 3 \ln 2 = \ln(2^3) \][/tex]
[tex]\[ 2 \ln 3 = \ln(3^2) \][/tex]

2. Simplification: Next, we simplify the expressions within the logarithms:
[tex]\[ \ln(2^3) = \ln(8) \][/tex]
[tex]\[ \ln(3^2) = \ln(9) \][/tex]

3. Product Rule: The product rule for logarithms states that [tex]\( \ln(a) + \ln(b) = \ln(ab) \)[/tex]. We now combine the two logarithmic expressions:
[tex]\[ \ln(8) + \ln(9) = \ln(8 \times 9) \][/tex]

4. Calculation: Multiply the numbers inside the logarithm:
[tex]\[ 8 \times 9 = 72 \][/tex]

5. Final Expression: Thus, the expression [tex]\( 3 \ln 2 + 2 \ln 3 \)[/tex] as a single logarithm is:
[tex]\[ \ln(72) \][/tex]

So, the correct answer is:
[tex]\[ \boxed{\ln(72)} \][/tex]