Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Sure! Let's solve the problem step-by-step to find out the amount [tex]\( P \)[/tex] that must be invested at an interest rate of 12% compounded continuously to obtain a balance of [tex]$130,000 in 10 years.
1. Identify the Given Values:
- Future value \( A = \$[/tex]130,000 \)
- Interest rate [tex]\( r = 0.12 \)[/tex] (which is 12% expressed as a decimal)
- Time period [tex]\( t = 10 \)[/tex] years
2. Formula for Continuous Compounding:
The formula for the future value with continuous compounding interest is given by:
[tex]\[ A = P \times e^{rt} \][/tex]
Here:
- [tex]\( A \)[/tex] is the future value
- [tex]\( P \)[/tex] is the principal amount (the amount to be invested)
- [tex]\( e \)[/tex] is the base of natural logarithms, approximately equal to 2.71828
- [tex]\( r \)[/tex] is the annual interest rate (as a decimal)
- [tex]\( t \)[/tex] is the time in years
3. Rearranging the Formula to Solve for [tex]\( P \)[/tex]:
To find the present value [tex]\( P \)[/tex], we need to rearrange the formula:
[tex]\[ P = \frac{A}{e^{rt}} \][/tex]
4. Substitution with Given Values:
Substitute [tex]\( A = 130000 \)[/tex], [tex]\( r = 0.12 \)[/tex], and [tex]\( t = 10 \)[/tex]:
[tex]\[ P = \frac{130000}{e^{0.12 \times 10}} \][/tex]
5. Calculation:
- Calculate the exponent:
[tex]\[ 0.12 \times 10 = 1.2 \][/tex]
- Calculate [tex]\( e^{1.2} \)[/tex]:
[tex]\[ e^{1.2} \approx 3.320117 \][/tex]
- Divide the future value by the calculated exponent:
[tex]\[ P = \frac{130000}{3.320117} \approx 39155.25 \][/tex]
Thus, the amount [tex]\( P \)[/tex] that must be invested today at an interest rate of 12% compounded continuously to obtain a balance of [tex]$130,000 in 10 years is approximately \(\$[/tex]39,155.25\).
Summary Table:
| Future Value ([tex]\(A\)[/tex]) | Interest Rate ([tex]\(r\)[/tex]) | Time ([tex]\(t\)[/tex]) | Present Value ([tex]\(P\)[/tex]) |
|----------------------|-----------------------|-----------------|------------------------|
| \[tex]$130,000 | 12% | 10 years | \$[/tex]39,155.25 |
Rounded to the nearest cent, the amount to be invested is [tex]\(\$39,155.25\)[/tex].
- Interest rate [tex]\( r = 0.12 \)[/tex] (which is 12% expressed as a decimal)
- Time period [tex]\( t = 10 \)[/tex] years
2. Formula for Continuous Compounding:
The formula for the future value with continuous compounding interest is given by:
[tex]\[ A = P \times e^{rt} \][/tex]
Here:
- [tex]\( A \)[/tex] is the future value
- [tex]\( P \)[/tex] is the principal amount (the amount to be invested)
- [tex]\( e \)[/tex] is the base of natural logarithms, approximately equal to 2.71828
- [tex]\( r \)[/tex] is the annual interest rate (as a decimal)
- [tex]\( t \)[/tex] is the time in years
3. Rearranging the Formula to Solve for [tex]\( P \)[/tex]:
To find the present value [tex]\( P \)[/tex], we need to rearrange the formula:
[tex]\[ P = \frac{A}{e^{rt}} \][/tex]
4. Substitution with Given Values:
Substitute [tex]\( A = 130000 \)[/tex], [tex]\( r = 0.12 \)[/tex], and [tex]\( t = 10 \)[/tex]:
[tex]\[ P = \frac{130000}{e^{0.12 \times 10}} \][/tex]
5. Calculation:
- Calculate the exponent:
[tex]\[ 0.12 \times 10 = 1.2 \][/tex]
- Calculate [tex]\( e^{1.2} \)[/tex]:
[tex]\[ e^{1.2} \approx 3.320117 \][/tex]
- Divide the future value by the calculated exponent:
[tex]\[ P = \frac{130000}{3.320117} \approx 39155.25 \][/tex]
Thus, the amount [tex]\( P \)[/tex] that must be invested today at an interest rate of 12% compounded continuously to obtain a balance of [tex]$130,000 in 10 years is approximately \(\$[/tex]39,155.25\).
Summary Table:
| Future Value ([tex]\(A\)[/tex]) | Interest Rate ([tex]\(r\)[/tex]) | Time ([tex]\(t\)[/tex]) | Present Value ([tex]\(P\)[/tex]) |
|----------------------|-----------------------|-----------------|------------------------|
| \[tex]$130,000 | 12% | 10 years | \$[/tex]39,155.25 |
Rounded to the nearest cent, the amount to be invested is [tex]\(\$39,155.25\)[/tex].
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.