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Which function is the result of vertically shrinking [tex]\( f(x) = 2(x+3)^2 \)[/tex] by a factor of [tex]\(\frac{1}{2}\)[/tex] and reflecting it across the [tex]\(x\)[/tex]-axis?

A) [tex]\(y = -\frac{1}{2}(x+3)^2\)[/tex]

B) [tex]\(y = \frac{1}{2}(x+3)^2\)[/tex]

C) [tex]\(y = (x+3)^2\)[/tex]

D) [tex]\(y = -(x+3)^2\)[/tex]


Sagot :

To determine the result of vertically shrinking the function [tex]\( f(x) = 2(x+3)^2 \)[/tex] by a factor of [tex]\( \frac{1}{2} \)[/tex] and then reflecting it across the [tex]\( x \)[/tex]-axis, we will proceed with the following steps:

### Step 1: Vertical Shrink by a Factor of [tex]\(\frac{1}{2}\)[/tex]
A vertical shrink of a function [tex]\( f(x) \)[/tex] by a factor of [tex]\( \frac{1}{2} \)[/tex] means that we need to multiply the function by [tex]\( \frac{1}{2} \)[/tex].

The original function is:
[tex]\[ f(x) = 2(x + 3)^2 \][/tex]

After applying the vertical shrink:
[tex]\[ g(x) = \frac{1}{2} \cdot 2(x + 3)^2 \][/tex]
[tex]\[ g(x) = (x + 3)^2 \][/tex]

### Step 2: Reflect Across the [tex]\( x \)[/tex]-Axis
Reflecting a function across the [tex]\( x \)[/tex]-axis involves multiplying the entire function by [tex]\(-1\)[/tex].

The function after the vertical shrink is:
[tex]\[ g(x) = (x + 3)^2 \][/tex]

Reflecting this function across the [tex]\( x \)[/tex]-axis:
[tex]\[ h(x) = - (x + 3)^2 \][/tex]

### Conclusion
The function resulting from first vertically shrinking [tex]\( f(x) = 2(x+3)^2 \)[/tex] by a factor of [tex]\( \frac{1}{2} \)[/tex] and then reflecting it across the [tex]\( x \)[/tex]-axis is:
[tex]\[ h(x) = - (x + 3)^2 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{D \: y = -(x + 3)^2} \][/tex]