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If you graph the system of inequalities given below, which points would lie in the solution set?

[tex]\[
\begin{array}{l}
x - y \geq -4 \\
2x - y \leq 5 \\
2y + x \ \textgreater \ 1
\end{array}
\][/tex]

A. [tex]\((-2, 3)\)[/tex]
B. [tex]\((-1, 3)\)[/tex]
C. [tex]\((0, 0)\)[/tex]
D. [tex]\((2, -2)\)[/tex]
E. [tex]\((3, 5)\)[/tex]

Sagot :

To determine which points lie in the solution set of the given system of inequalities, we need to check each point individually against all the inequalities:

[tex]\[ \begin{array}{l} x-y \geq -4 \\ 2x-y \leq 5 \\ 2y+x > 1 \end{array} \][/tex]

Point [tex]\((-2, 3)\)[/tex]:

1. Check [tex]\( x - y \geq -4 \)[/tex]:
[tex]\[ -2 - 3 \geq -4 \quad \Rightarrow \quad -5 \geq -4 \quad \text{False} \][/tex]

Since this point does not satisfy the first inequality, it is not in the solution set.

Point [tex]\((-1, 3)\)[/tex]:

1. Check [tex]\( x - y \geq -4 \)[/tex]:
[tex]\[ -1 - 3 \geq -4 \quad \Rightarrow \quad -4 \geq -4 \quad \text{True} \][/tex]
2. Check [tex]\( 2x - y \leq 5 \)[/tex]:
[tex]\[ 2(-1) - 3 \leq 5 \quad \Rightarrow \quad -2 - 3 \leq 5 \quad \Rightarrow \quad -5 \leq 5 \quad \text{True} \][/tex]
3. Check [tex]\( 2y + x > 1 \)[/tex]:
[tex]\[ 2(3) + (-1) > 1 \quad \Rightarrow \quad 6 - 1 > 1 \quad \Rightarrow \quad 5 > 1 \quad \text{True} \][/tex]

Since this point satisfies all the inequalities, it is in the solution set.

Point [tex]\((0, 0)\)[/tex]:

1. Check [tex]\( x - y \geq -4 \)[/tex]:
[tex]\[ 0 - 0 \geq -4 \quad \Rightarrow \quad 0 \geq -4 \quad \text{True} \][/tex]
2. Check [tex]\( 2x - y \leq 5 \)[/tex]:
[tex]\[ 2(0) - 0 \leq 5 \quad \Rightarrow \quad 0 \leq 5 \quad \text{True} \][/tex]
3. Check [tex]\( 2y + x > 1 \)[/tex]:
[tex]\[ 2(0) + 0 > 1 \quad \Rightarrow \quad 0 > 1 \quad \text{False} \][/tex]

Since this point does not satisfy the third inequality, it is not in the solution set.

Point [tex]\((2, -2)\)[/tex]:

1. Check [tex]\( x - y \geq -4 \)[/tex]:
[tex]\[ 2 - (-2) \geq -4 \quad \Rightarrow \quad 2 + 2 \geq -4 \quad \Rightarrow \quad 4 \geq -4 \quad \text{True} \][/tex]
2. Check [tex]\( 2x - y \leq 5 \)[/tex]:
[tex]\[ 2(2) - (-2) \leq 5 \quad \Rightarrow \quad 4 + 2 \leq 5 \quad \Rightarrow \quad 6 \leq 5 \quad \text{False} \][/tex]

Since this point does not satisfy the second inequality, it is not in the solution set.

Point [tex]\((3, 5)\)[/tex]:

1. Check [tex]\( x - y \geq -4 \)[/tex]:
[tex]\[ 3 - 5 \geq -4 \quad \Rightarrow \quad -2 \geq -4 \quad \text{True} \][/tex]
2. Check [tex]\( 2x - y \leq 5 \)[/tex]:
[tex]\[ 2(3) - 5 \leq 5 \quad \Rightarrow \quad 6 - 5 \leq 5 \quad \Rightarrow \quad 1 \leq 5 \quad \text{True} \][/tex]
3. Check [tex]\( 2y + x > 1 \)[/tex]:
[tex]\[ 2(5) + 3 > 1 \quad \Rightarrow \quad 10 + 3 > 1 \quad \Rightarrow \quad 13 > 1 \quad \text{True} \][/tex]

Since this point satisfies all the inequalities, it is in the solution set.

Summary:

The points that lie in the solution set of the given system of inequalities are:

- [tex]\((-1, 3)\)[/tex]
- [tex]\((3, 5)\)[/tex]
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