Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To find the force on the ball as it begins to fall, we need to use Newton's second law of motion, which states that the force [tex]\( F \)[/tex] acting on an object is given by the product of its mass [tex]\( m \)[/tex] and the acceleration due to gravity [tex]\( g \)[/tex]. Mathematically, this is represented as:
[tex]\[ F = m \cdot g \][/tex]
We are given the following values:
- Mass of the ball, [tex]\( m = 0.21 \, \text{kg} \)[/tex]
- Acceleration due to gravity, [tex]\( g = 9.81 \, \text{m/s}^2 \)[/tex]
Now let's substitute the given values into the formula:
[tex]\[ F = 0.21 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \][/tex]
When we perform the multiplication:
[tex]\[ F = 2.06 \, \text{N} \][/tex]
Therefore, the force on the ball as it begins to fall is [tex]\( 2.06 \, \text{N} \)[/tex].
From the given options, the correct answer is:
D. 2.06 N
[tex]\[ F = m \cdot g \][/tex]
We are given the following values:
- Mass of the ball, [tex]\( m = 0.21 \, \text{kg} \)[/tex]
- Acceleration due to gravity, [tex]\( g = 9.81 \, \text{m/s}^2 \)[/tex]
Now let's substitute the given values into the formula:
[tex]\[ F = 0.21 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \][/tex]
When we perform the multiplication:
[tex]\[ F = 2.06 \, \text{N} \][/tex]
Therefore, the force on the ball as it begins to fall is [tex]\( 2.06 \, \text{N} \)[/tex].
From the given options, the correct answer is:
D. 2.06 N
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.