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Consider the following intermediate chemical equations.

[tex]\[
\begin{array}{l}
2P (s) + 3Cl_2(g) \rightarrow 2PCl_3(l) \\
PCl_3(l) + Cl_2(g) \rightarrow PCl_5(s)
\end{array}
\][/tex]

When you combine the intermediate chemical equations, which substance do you cancel out?

A. [tex]\(P\)[/tex]

B. [tex]\(Cl_2\)[/tex]

C. [tex]\(PCl_3\)[/tex]

D. [tex]\(PCl_5\)[/tex]

Sagot :

GinnyAnswer
To determine which substance gets canceled out when combining the given intermediate chemical equations, let's look at each reaction and combine them step-by-step.

Consider the intermediate chemical equations provided:
[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \][/tex]

[tex]\[ PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s) \][/tex]

### Step-by-Step Combination

1. Write down both equations:

First equation:
[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \][/tex]

Second equation:
[tex]\[ PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s) \][/tex]

2. Search for the common substance:

Identify a substance that appears on both sides of the reactions. Specifically, we see that [tex]\(PCl_3\)[/tex] appears as a product in the first reaction and as a reactant in the second reaction.

3. Combine the equations:

Combine the two equations and make sure to cancel out any substances that appear on both sides:

From the first equation:
[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \][/tex]

From the second equation:
[tex]\[ PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s) \][/tex]

In combining these, the substance [tex]\(PCl_3 (l)\)[/tex] appears on the product side in the first equation and on the reactant side in the second equation. Thus, we can cancel out [tex]\(PCl_3 (l)\)[/tex]:

[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \][/tex]
[tex]\[ 2 PCl_3 (l) + 2 Cl_2 (g) \rightarrow 2 PCl_5 (s) \][/tex]

Simplifying:
[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \rightarrow 2 PCl_3 (l) + 2 Cl_2 (g) \rightarrow 2 PCl_5 (s) \][/tex]

After canceling [tex]\(PCl_3 (l)\)[/tex], we get:
[tex]\[ 2 P (s) + 3 Cl_2 (g) + 2 Cl_2 (g) \rightarrow 2 PCl_5 (s) \][/tex]

Simplify further:
[tex]\[ 2 P (s) + 5 Cl_2 (g) \rightarrow 2 PCl_5 (s) \][/tex]

### Conclusion

When combining the intermediate chemical equations, the substance that gets canceled out in the overall reaction is [tex]\( PCl_3 \)[/tex].
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