To determine how oxygen appears in the final chemical equation derived from the given intermediate chemical equations, let’s combine the two equations step by step. Here are the given intermediate equations:
1. [tex]\( C(s) + \frac{1}{2} O_2(g) \rightarrow CO(g) \)[/tex]
2. [tex]\( CO(g) + \frac{1}{2} O_2(g) \rightarrow CO_2(g) \)[/tex]
Step-by-step combination:
1. Add the two reactions:
[tex]\[
\begin{aligned}
&\text{First Equation:} & C(s) + \frac{1}{2} O_2(g) &\rightarrow CO(g) \\
&\text{Second Equation:} & CO(g) + \frac{1}{2} O_2(g) &\rightarrow CO_2(g) \\
\end{aligned}
\][/tex]
2. When we add these equations together, we combine the reactants and the products:
[tex]\[
C(s) + \frac{1}{2} O_2(g) + CO(g) + \frac{1}{2} O_2(g) \rightarrow CO(g) + CO_2(g)
\][/tex]
3. Simplify the equation by canceling out the [tex]\( CO(g) \)[/tex] on both the reactant and product sides:
[tex]\[
C(s) + \frac{1}{2} O_2(g) + \frac{1}{2} O_2(g) \rightarrow CO_2(g)
\][/tex]
4. Combine the [tex]\( O_2(g) \)[/tex] terms on the left side:
[tex]\[
C(s) + 1 O_2(g) \rightarrow CO_2(g)
\][/tex]
After combining and simplifying the two intermediate reactions, the overall reaction becomes:
[tex]\[
C(s) + O_2(g) \rightarrow CO_2(g)
\][/tex]
From this final combined equation, it is evident that:
- [tex]\( O_2(g) \)[/tex] appears as a reactant.
Therefore, the correct answer regarding how oxygen appears in the final chemical equation is:
[tex]\[
O_2(g) \text{ as a reactant}
\][/tex]
