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Sagot :
Sure, let's break down each part of the question step-by-step.
### a) Relation between ∠P and ∠R
In a cyclic quadrilateral, the opposite angles are supplementary. This means that their sum is 180°.
Therefore, the relation between ∠P and ∠R is:
[tex]\[ \angle P + \angle R = 180^\circ \][/tex]
### b) Find the value of [tex]\( x \)[/tex]
Given:
[tex]\[ \angle P = 2x^\circ \][/tex]
[tex]\[ \angle R = 4x^\circ \][/tex]
Since ∠P and ∠R are opposite angles in a cyclic quadrilateral, we have:
[tex]\[ 2x + 4x = 180^\circ \][/tex]
Combine like terms:
[tex]\[ 6x = 180^\circ \][/tex]
To solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{180}{6} \][/tex]
[tex]\[ x = 30^\circ \][/tex]
### c) Experimentally verify the angle at the center is double the angle at the circumference standing on the same arc
For this part, you will need to conduct a practical experiment using two circles, each with a radius of at least 3 cm. Follow these steps:
1. Draw a Circle: Take a compass and draw a circle with a radius of at least 3 cm.
2. Mark an Arc: Choose any two points on the circumference of the circle; name them A and B.
3. Angle at the Circumference (∠APB): From point P on the circumference (different from points A and B), draw lines PA and PB to form the angle ∠APB.
4. Angle at the Center (∠AOB): Now, draw lines from the center of the circle O to points A and B to form the angle ∠AOB.
5. Measuring the Angles:
- Measure the angle ∠APB using a protractor.
- Measure the angle ∠AOB using a protractor.
You should find that:
[tex]\[ \angle AOB = 2 \times \angle APB \][/tex]
Repeat the procedure with the second circle to confirm your results. The experimental verification should show that the angle subtended at the center of a circle is indeed double the angle subtended at the circumference by the same arc, consistent with the theoretical principle.
This concludes the detailed step-by-step solution to the given question.
### a) Relation between ∠P and ∠R
In a cyclic quadrilateral, the opposite angles are supplementary. This means that their sum is 180°.
Therefore, the relation between ∠P and ∠R is:
[tex]\[ \angle P + \angle R = 180^\circ \][/tex]
### b) Find the value of [tex]\( x \)[/tex]
Given:
[tex]\[ \angle P = 2x^\circ \][/tex]
[tex]\[ \angle R = 4x^\circ \][/tex]
Since ∠P and ∠R are opposite angles in a cyclic quadrilateral, we have:
[tex]\[ 2x + 4x = 180^\circ \][/tex]
Combine like terms:
[tex]\[ 6x = 180^\circ \][/tex]
To solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{180}{6} \][/tex]
[tex]\[ x = 30^\circ \][/tex]
### c) Experimentally verify the angle at the center is double the angle at the circumference standing on the same arc
For this part, you will need to conduct a practical experiment using two circles, each with a radius of at least 3 cm. Follow these steps:
1. Draw a Circle: Take a compass and draw a circle with a radius of at least 3 cm.
2. Mark an Arc: Choose any two points on the circumference of the circle; name them A and B.
3. Angle at the Circumference (∠APB): From point P on the circumference (different from points A and B), draw lines PA and PB to form the angle ∠APB.
4. Angle at the Center (∠AOB): Now, draw lines from the center of the circle O to points A and B to form the angle ∠AOB.
5. Measuring the Angles:
- Measure the angle ∠APB using a protractor.
- Measure the angle ∠AOB using a protractor.
You should find that:
[tex]\[ \angle AOB = 2 \times \angle APB \][/tex]
Repeat the procedure with the second circle to confirm your results. The experimental verification should show that the angle subtended at the center of a circle is indeed double the angle subtended at the circumference by the same arc, consistent with the theoretical principle.
This concludes the detailed step-by-step solution to the given question.
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