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Sagot :
Certainly! Let's solve the system of equations using the elimination method step-by-step.
Given equations:
[tex]\[ \begin{cases} 3x + y = 5 \\ 2x - 2y = -2 \end{cases} \][/tex]
1. Simplify the second equation:
Divide the second equation by 2 to simplify it:
[tex]\[ \frac{2x - 2y}{2} = \frac{-2}{2} \][/tex]
Simplifying, we get:
[tex]\[ x - y = -1 \][/tex]
2. Rewrite the system:
Now, we have a simpler system of equations:
[tex]\[ \begin{cases} 3x + y = 5 \\ x - y = -1 \end{cases} \][/tex]
3. Add the equations to eliminate [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} &3x + y + x - y = 5 + (-1) \\ &4x = 4 \\ &x = 1 \end{aligned} \][/tex]
4. Substitute [tex]\( x = 1 \)[/tex] back into the simpler equation [tex]\( x - y = -1 \)[/tex] to find [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} 1 - y &= -1 \\ -y &= -1 - 1 \\ -y &= -2 \\ y &= 2 \end{aligned} \][/tex]
Hence, the solution to the system of equations is:
[tex]\[ (x, y) = (1, 2) \][/tex]
Therefore, the correct answer is:
[tex]\[ (1, 2) \][/tex]
Given equations:
[tex]\[ \begin{cases} 3x + y = 5 \\ 2x - 2y = -2 \end{cases} \][/tex]
1. Simplify the second equation:
Divide the second equation by 2 to simplify it:
[tex]\[ \frac{2x - 2y}{2} = \frac{-2}{2} \][/tex]
Simplifying, we get:
[tex]\[ x - y = -1 \][/tex]
2. Rewrite the system:
Now, we have a simpler system of equations:
[tex]\[ \begin{cases} 3x + y = 5 \\ x - y = -1 \end{cases} \][/tex]
3. Add the equations to eliminate [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} &3x + y + x - y = 5 + (-1) \\ &4x = 4 \\ &x = 1 \end{aligned} \][/tex]
4. Substitute [tex]\( x = 1 \)[/tex] back into the simpler equation [tex]\( x - y = -1 \)[/tex] to find [tex]\( y \)[/tex]:
[tex]\[ \begin{aligned} 1 - y &= -1 \\ -y &= -1 - 1 \\ -y &= -2 \\ y &= 2 \end{aligned} \][/tex]
Hence, the solution to the system of equations is:
[tex]\[ (x, y) = (1, 2) \][/tex]
Therefore, the correct answer is:
[tex]\[ (1, 2) \][/tex]
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