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Sagot :
To determine which statement is correct about the freezing point of the unknown substance, let's carefully examine the given data table and understand the transitions between states of matter:
[tex]\[ \begin{tabular}{|c|c|c|} \hline \begin{tabular}{c} Time \\ (minutes) \end{tabular} & \begin{tabular}{c} Temperature \\ (degrees Celsius) \end{tabular} & State of matter \\ \hline 0 & 25 & Liquid \\ \hline 2 & 23 & Liquid \\ \hline 4 & 18 & \\ \hline 6 & 18 & \\ \hline 8 & 18 & Solid \\ \hline 10 & 15 & Solid \\ \hline 12 & 10 & \\ \hline \end{tabular} \][/tex]
1. Analyzing the Data Points:
- At 0 minutes, the temperature is 25°C and the substance is in a liquid state.
- At 2 minutes, the temperature is 23°C and the substance is still in a liquid state.
- At 4 minutes, the temperature is 18°C, but the state of matter is not given.
- At 6 minutes, the temperature remains 18°C, with the state of matter still not given.
- At 8 minutes, the temperature is 18°C and the substance has transitioned to a solid state.
- At 10 minutes, the temperature drops to 15°C and the substance remains a solid.
- At 12 minutes, the temperature further drops to 10°C, and the state is not specified.
2. Freezing Point Determination:
- The freezing point of a substance is the temperature at which it transitions from a liquid to a solid.
- Observing the data, at both 2 minutes (23°C) and 4 minutes (18°C), the state of matter at 23°C remains liquid.
- The transition from liquid to solid can be observed between the 2-minute mark (23°C) and the 8-minute mark (18°C).
3. Conclusion:
- Since the substance starts as a liquid and is observed as a solid at 18°C, we can conclude that it transitions from liquid to solid at 18°C.
Therefore, the correct statement is:
- Its freezing point is [tex]\( 18^{\circ} \text{C} \)[/tex].
[tex]\[ \begin{tabular}{|c|c|c|} \hline \begin{tabular}{c} Time \\ (minutes) \end{tabular} & \begin{tabular}{c} Temperature \\ (degrees Celsius) \end{tabular} & State of matter \\ \hline 0 & 25 & Liquid \\ \hline 2 & 23 & Liquid \\ \hline 4 & 18 & \\ \hline 6 & 18 & \\ \hline 8 & 18 & Solid \\ \hline 10 & 15 & Solid \\ \hline 12 & 10 & \\ \hline \end{tabular} \][/tex]
1. Analyzing the Data Points:
- At 0 minutes, the temperature is 25°C and the substance is in a liquid state.
- At 2 minutes, the temperature is 23°C and the substance is still in a liquid state.
- At 4 minutes, the temperature is 18°C, but the state of matter is not given.
- At 6 minutes, the temperature remains 18°C, with the state of matter still not given.
- At 8 minutes, the temperature is 18°C and the substance has transitioned to a solid state.
- At 10 minutes, the temperature drops to 15°C and the substance remains a solid.
- At 12 minutes, the temperature further drops to 10°C, and the state is not specified.
2. Freezing Point Determination:
- The freezing point of a substance is the temperature at which it transitions from a liquid to a solid.
- Observing the data, at both 2 minutes (23°C) and 4 minutes (18°C), the state of matter at 23°C remains liquid.
- The transition from liquid to solid can be observed between the 2-minute mark (23°C) and the 8-minute mark (18°C).
3. Conclusion:
- Since the substance starts as a liquid and is observed as a solid at 18°C, we can conclude that it transitions from liquid to solid at 18°C.
Therefore, the correct statement is:
- Its freezing point is [tex]\( 18^{\circ} \text{C} \)[/tex].
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