Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A card is drawn one at a time from a well-shuffled deck of 52 cards. In 11 repetitions of this experiment, 2 kings are drawn. If [tex]$E$[/tex] is the event in which a king is drawn, find the experimental probability [tex]$P(E)$[/tex].

[tex] P(E) = \frac{2}{11} [/tex]


Sagot :

Certainly! Let's solve this problem step by step.

### Step 1: Determine the Total Number of Repetitions
First, we know that the experiment, which involves drawing a card from a well-shuffled deck of 52 cards, was repeated 11 times. So, the total number of repetitions is:
[tex]$ \text{Total repetitions} = 11 $[/tex]

### Step 2: Identify the Number of Times the Event Occurs
Next, we are given that the event [tex]\(E\)[/tex], which is drawing a king, occurred 2 times in these 11 repetitions. So, the number of times a king was drawn is:
[tex]$ \text{Number of times a king was drawn} = 2 $[/tex]

### Step 3: Calculate the Experimental Probability
The experimental probability [tex]\(P(E)\)[/tex] of an event [tex]\(E\)[/tex] is calculated by dividing the number of times the event occurs by the total number of trials. Therefore, the experimental probability [tex]\(P(E)\)[/tex] is given by:
[tex]$ P(E) = \frac{\text{Number of times a king was drawn}}{\text{Total repetitions}} $[/tex]

Substituting the given values:
[tex]$ P(E) = \frac{2}{11} $[/tex]

### Step 4: Simplify the Probability Fraction
In this case, the fraction [tex]\( \frac{2}{11} \)[/tex] is already in its simplest form. Converting this to a decimal for clarification gives approximately:
[tex]$ P(E) \approx 0.18181818181818182 $[/tex]

So, the experimental probability [tex]\(P(E)\)[/tex] of drawing a king in this experiment is:
[tex]$ P(E) = \frac{2}{11} \approx 0.1818 $[/tex]

Therefore, the final result for the experimental probability [tex]\(P(E)\)[/tex] is:
[tex]$ P(E) = \frac{2}{11} $[/tex]