Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Let's systematically analyze each of the given functions to determine which one can have a range that includes [tex]\(-4\)[/tex].
1. Function: [tex]\( y = \sqrt{x} - 5 \)[/tex]
Let's see if it is possible for [tex]\( y = -4 \)[/tex]:
[tex]\[ -4 = \sqrt{x} - 5 \][/tex]
By adding 5 to both sides, we obtain:
[tex]\[ 1 = \sqrt{x} \][/tex]
Squaring both sides to eliminate the square root, we get:
[tex]\[ x = 1 \][/tex]
Since [tex]\( x = 1 \)[/tex] is a valid value (it's non-negative), [tex]\( y = \sqrt{x} - 5 \)[/tex] can indeed equal [tex]\(-4\)[/tex] when [tex]\( x = 1 \)[/tex].
Thus, the range of [tex]\( y = \sqrt{x} - 5 \)[/tex] includes [tex]\(-4\)[/tex].
2. Function: [tex]\( y = \sqrt{x} + 5 \)[/tex]
Similarly, we try to see if [tex]\( y = -4 \)[/tex] is possible:
[tex]\[ -4 = \sqrt{x} + 5 \][/tex]
Subtracting 5 from both sides, we find:
[tex]\[ -9 = \sqrt{x} \][/tex]
This result is impossible because the square root of [tex]\( x \)[/tex] (where [tex]\( x \geq 0 \)[/tex]) is always non-negative. Thus, [tex]\( y = \sqrt{x} + 5 \)[/tex] cannot have a value of [tex]\(-4\)[/tex].
3. Function: [tex]\( y = \sqrt{x+5} \)[/tex]
Check if [tex]\( y = -4 \)[/tex]:
[tex]\[ -4 = \sqrt{x+5} \][/tex]
Similar to the previous case, squaring both sides gives:
[tex]\[ 16 = x + 5 \][/tex]
Solving for [tex]\( x \)[/tex], we get:
[tex]\[ x = 16 - 5 = 11 \][/tex]
However, when we checked this previously, squaring gave an incorrect condition since square roots do not yield negative numbers.
In this particular circumstance, [tex]\( y = \sqrt{x+5} \)[/tex] cannot equal [tex]\(-4\)[/tex].
4. Function: [tex]\( y = \sqrt{x-5} \)[/tex]
Let's investigate if [tex]\( y = -4 \)[/tex]:
[tex]\[ -4 = \sqrt{x-5} \][/tex]
Squaring both sides results in:
[tex]\[ 16 = x - 5 \][/tex]
Solving for [tex]\( x \)[/tex], we get:
[tex]\[ x = 16 + 5 = 21 \][/tex]
Once again, this situation results from incorrectly calculating negative roots.
Therefore, [tex]\( y = \sqrt{x-5} \)[/tex] also cannot equal [tex]\(-4\)[/tex].
From this detailed examination, we conclude that the range of the function [tex]\( y = \sqrt{x} - 5 \)[/tex] includes [tex]\(-4\)[/tex].
1. Function: [tex]\( y = \sqrt{x} - 5 \)[/tex]
Let's see if it is possible for [tex]\( y = -4 \)[/tex]:
[tex]\[ -4 = \sqrt{x} - 5 \][/tex]
By adding 5 to both sides, we obtain:
[tex]\[ 1 = \sqrt{x} \][/tex]
Squaring both sides to eliminate the square root, we get:
[tex]\[ x = 1 \][/tex]
Since [tex]\( x = 1 \)[/tex] is a valid value (it's non-negative), [tex]\( y = \sqrt{x} - 5 \)[/tex] can indeed equal [tex]\(-4\)[/tex] when [tex]\( x = 1 \)[/tex].
Thus, the range of [tex]\( y = \sqrt{x} - 5 \)[/tex] includes [tex]\(-4\)[/tex].
2. Function: [tex]\( y = \sqrt{x} + 5 \)[/tex]
Similarly, we try to see if [tex]\( y = -4 \)[/tex] is possible:
[tex]\[ -4 = \sqrt{x} + 5 \][/tex]
Subtracting 5 from both sides, we find:
[tex]\[ -9 = \sqrt{x} \][/tex]
This result is impossible because the square root of [tex]\( x \)[/tex] (where [tex]\( x \geq 0 \)[/tex]) is always non-negative. Thus, [tex]\( y = \sqrt{x} + 5 \)[/tex] cannot have a value of [tex]\(-4\)[/tex].
3. Function: [tex]\( y = \sqrt{x+5} \)[/tex]
Check if [tex]\( y = -4 \)[/tex]:
[tex]\[ -4 = \sqrt{x+5} \][/tex]
Similar to the previous case, squaring both sides gives:
[tex]\[ 16 = x + 5 \][/tex]
Solving for [tex]\( x \)[/tex], we get:
[tex]\[ x = 16 - 5 = 11 \][/tex]
However, when we checked this previously, squaring gave an incorrect condition since square roots do not yield negative numbers.
In this particular circumstance, [tex]\( y = \sqrt{x+5} \)[/tex] cannot equal [tex]\(-4\)[/tex].
4. Function: [tex]\( y = \sqrt{x-5} \)[/tex]
Let's investigate if [tex]\( y = -4 \)[/tex]:
[tex]\[ -4 = \sqrt{x-5} \][/tex]
Squaring both sides results in:
[tex]\[ 16 = x - 5 \][/tex]
Solving for [tex]\( x \)[/tex], we get:
[tex]\[ x = 16 + 5 = 21 \][/tex]
Once again, this situation results from incorrectly calculating negative roots.
Therefore, [tex]\( y = \sqrt{x-5} \)[/tex] also cannot equal [tex]\(-4\)[/tex].
From this detailed examination, we conclude that the range of the function [tex]\( y = \sqrt{x} - 5 \)[/tex] includes [tex]\(-4\)[/tex].
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.