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A system of equations is shown:

[tex]\[
\begin{array}{l}
2x = 5y + 4 \\
3x - 2y = -16
\end{array}
\][/tex]

What is the solution to this system of equations?

A. [tex]\((-8, -4)\)[/tex]
B. [tex]\((8, 4)\)[/tex]
C. [tex]\((-4, -8)\)[/tex]
D. [tex]\((4, 8)\)[/tex]


Sagot :

To solve the system of equations:
[tex]\[ \begin{cases} 2x = 5y + 4 \\ 3x - 2y = -16 \end{cases} \][/tex]

we can use the method of substitution or elimination. Let's go step by step using substitution in this case.

1. Equation 1: [tex]\(2x = 5y + 4\)[/tex]

Solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{5y + 4}{2} \][/tex]

2. Substitute [tex]\(x\)[/tex] in Equation 2:
[tex]\[ 3 \left( \frac{5y + 4}{2} \right) - 2y = -16 \][/tex]

3. Multiply both sides by 2 to clear the fraction:
[tex]\[ 3(5y + 4) - 4y = -32 \][/tex]

4. Distribute and simplify:
[tex]\[ 15y + 12 - 4y = -32 \][/tex]
[tex]\[ 11y + 12 = -32 \][/tex]

5. Isolate [tex]\(y\)[/tex]:
[tex]\[ 11y = -32 - 12 \][/tex]
[tex]\[ 11y = -44 \][/tex]
[tex]\[ y = \frac{-44}{11} \][/tex]
[tex]\[ y = -4 \][/tex]

6. Substitute [tex]\(y\)[/tex] back into Equation 1 to find [tex]\(x\)[/tex]:
[tex]\[ 2x = 5(-4) + 4 \][/tex]
[tex]\[ 2x = -20 + 4 \][/tex]
[tex]\[ 2x = -16 \][/tex]
[tex]\[ x = \frac{-16}{2} \][/tex]
[tex]\[ x = -8 \][/tex]

Therefore, the solution to the system of equations is [tex]\((-8, -4)\)[/tex].

To determine which option matches our solution:

- [tex]\((-8, -4)\)[/tex]: Yes, this matches our solution.

Thus, the correct answer is [tex]\((-8, -4)\)[/tex], which corresponds to the option 1.
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