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Sagot :
To find the probability that there were exactly 2 customers in line, you can use the formula for probability:
[tex]\[ P(2) = \frac{\text{Frequency of 2 customers}}{\text{Total Frequency}} \][/tex]
Given the data:
- The frequency of exactly 2 customers is 9.
- The total frequency (or total number of observations) is 30.
Plugging these values into the formula:
[tex]\[ P(2) = \frac{9}{30} \][/tex]
To simplify this fraction, you divide both the numerator and the denominator by their greatest common divisor, which is 3:
[tex]\[ P(2) = \frac{9 \div 3}{30 \div 3} \][/tex]
[tex]\[ P(2) = \frac{3}{10} \][/tex]
Thus, the probability that there were exactly 2 customers in line is:
[tex]\[ P(2) = 0.3 \][/tex]
So, the probability of exactly 2 customers in line at any given minute is 0.3 or 30%.
[tex]\[ P(2) = \frac{\text{Frequency of 2 customers}}{\text{Total Frequency}} \][/tex]
Given the data:
- The frequency of exactly 2 customers is 9.
- The total frequency (or total number of observations) is 30.
Plugging these values into the formula:
[tex]\[ P(2) = \frac{9}{30} \][/tex]
To simplify this fraction, you divide both the numerator and the denominator by their greatest common divisor, which is 3:
[tex]\[ P(2) = \frac{9 \div 3}{30 \div 3} \][/tex]
[tex]\[ P(2) = \frac{3}{10} \][/tex]
Thus, the probability that there were exactly 2 customers in line is:
[tex]\[ P(2) = 0.3 \][/tex]
So, the probability of exactly 2 customers in line at any given minute is 0.3 or 30%.
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