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## Sagot :

1.

**Substitute [tex]\( x = -2 \)[/tex] into both sides of the inequality:**

- The left side of the inequality is [tex]\( x^2 - 10x + 1 \)[/tex].

- The right side of the inequality is [tex]\( 20 + 5x \)[/tex].

2.

**Evaluate the left side:**

- Substitute [tex]\( x = -2 \)[/tex] into [tex]\( x^2 - 10x + 1 \)[/tex]:

[tex]\[ (-2)^2 - 10(-2) + 1 \][/tex]

- First, calculate [tex]\( (-2)^2 \)[/tex]:

[tex]\[ 4 \][/tex]

- Next, calculate [tex]\( -10 \times (-2) \)[/tex]:

[tex]\[ 20 \][/tex]

- Now, add these results together along with 1:

[tex]\[ 4 + 20 + 1 = 25 \][/tex]

3.

**Evaluate the right side:**

- Substitute [tex]\( x = -2 \)[/tex] into [tex]\( 20 + 5x \)[/tex]:

[tex]\[ 20 + 5(-2) \][/tex]

- First, calculate [tex]\( 5 \times (-2) \)[/tex]:

[tex]\[ -10 \][/tex]

- Now, add this result to 20:

[tex]\[ 20 - 10 = 10 \][/tex]

4.

**Compare the two sides:**

- The left side evaluates to 25.

- The right side evaluates to 10.

5.

**Determine if the inequality holds:**

- We want to see if [tex]\( 25 < 10 \)[/tex].

6.

**Conclusion:**

- Since [tex]\( 25 \)[/tex] is not less than [tex]\( 10 \)[/tex], the inequality does not hold for [tex]\( x = -2 \)[/tex].

Therefore, for [tex]\( x = -2 \)[/tex], the inequality [tex]\( x^2 - 10x + 1 < 20 + 5x \)[/tex] does not hold true.