dchagoya
Answered

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Use long division.
 (30x³+4x²-150)÷(3x-5)

Sagot :

kate200468
[tex]30x^3+4x^2-150=10x^2(3x-5)+18x(3x-5)+30(3x-5)=\\ \\=(3x-5)(10x^2+18x+30)\\\\ \\ (30x^3+4x^2-150):(3x-5)= \frac{(3x-5)(10x^2+18x+30)}{3x-5} =10x^2+18x+30[/tex]
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