Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

I need help factoring  quadratic equation

10x^2+31x+24

Sagot :

Lilith
[tex]10x^2+31x+24 = \\ \\=10x^2+31x-15x+15x+24 =\\ \\= 10x^2+16x+15x+24 =\\ \\=2x(5x+8) +3(5x+8)=\\ \\=(5x+8)(2x+3)[/tex]
[tex]10x^2+31x+24\\\\a=10;\ b=31;\ c=24\\\\\Delta=b^2-4ac\\\\\Delta=31^2-4\cdot10\cdot24=961-960=1\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt1=1\\\\x_1=\frac{-31-1}{2\cdot10}=\frac{-32}{20}=-\frac{8}{5};\ x_2=\frac{-31+1}{2\cdot10}=\frac{-30}{20}=-\frac{3}{2}\\\\10x^2+31x+24=10(x+\frac{8}{5})(x+\frac{3}{2})=5(x+\frac{8}{5})\cdot2(x+\frac{3}{2})\\\\=(5x+8)(2x+3)[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.