Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

I need help factoring  quadratic equation

10x^2+31x+24

Sagot :

Lilith
[tex]10x^2+31x+24 = \\ \\=10x^2+31x-15x+15x+24 =\\ \\= 10x^2+16x+15x+24 =\\ \\=2x(5x+8) +3(5x+8)=\\ \\=(5x+8)(2x+3)[/tex]
[tex]10x^2+31x+24\\\\a=10;\ b=31;\ c=24\\\\\Delta=b^2-4ac\\\\\Delta=31^2-4\cdot10\cdot24=961-960=1\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt1=1\\\\x_1=\frac{-31-1}{2\cdot10}=\frac{-32}{20}=-\frac{8}{5};\ x_2=\frac{-31+1}{2\cdot10}=\frac{-30}{20}=-\frac{3}{2}\\\\10x^2+31x+24=10(x+\frac{8}{5})(x+\frac{3}{2})=5(x+\frac{8}{5})\cdot2(x+\frac{3}{2})\\\\=(5x+8)(2x+3)[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.