Answered

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Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)? HELP ME PLEASE!!


Answer Choices:


A.) (x - 1)2 + (y - 1)2 = 17
B.) (x + 5)2 + y2 = 17
C.) (x + 5)2 + y2 = 24
D.) (x - 5)2 + y2 = 17



Sagot :

Ryan2
a) first we will calculate the distance between center and given point because this is the radius of circle:

[tex]d=\sqrt{(1-5)^2+(1-0)^2}\\ \\ d=\sqrt{(-4)^2+1}=\sqrt{17}[/tex]

b) Now we will write the equation of the circle:

[tex]\boxed{\boxed{(x-5)^2+y^2=17}}[/tex]
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