Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)? HELP ME PLEASE!!


Answer Choices:


A.) (x - 1)2 + (y - 1)2 = 17
B.) (x + 5)2 + y2 = 17
C.) (x + 5)2 + y2 = 24
D.) (x - 5)2 + y2 = 17

Sagot :

Ryan2
a) first we will calculate the distance between center and given point because this is the radius of circle:

[tex]d=\sqrt{(1-5)^2+(1-0)^2}\\ \\ d=\sqrt{(-4)^2+1}=\sqrt{17}[/tex]

b) Now we will write the equation of the circle:

[tex]\boxed{\boxed{(x-5)^2+y^2=17}}[/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.