Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Verify
(2cos2x)/(sin2x) - cotx - tanx = -2tanx


Sagot :

Ryan2
Remember:

[tex]\boxed{sin(2x)=2.sinx.cosx}\\ \\ and\\ \\ \boxed{cos(2x)=cos^2x-sin^2x}[/tex]


[tex]\frac{2cos2x}{sin2x}-cotx-tanx=\\ \\ \frac{2(cos^2x-sin^2x)}{2sinx.cosx}-\frac{cosx}{sinx}-\frac{sinx}{cosx}=\\ \\ \frac{cos^2x-sin^2x}{sinx.cosx}-\frac{cosx}{sinx}-\frac{sinx}{cosx}=\\ \\ \frac{cos^2x-sin^2x-cos^2x-sin^2x}{sinx.cosx}=\\ \\ \frac{-2sin^2x}{sinx.cosx}=\\ \\ \frac{-2sinx}{cosx}=-2.tanx[/tex]
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.