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What is the alpha decay of Radon-198?

Sagot :

chrissybrackeen
86198Rn => 24He + 84194Po

The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.

The alpha decay of Radon-198 produces alpha particle and ¹⁹⁴₈₄Po.

What is alpha decay?

Alpha decay is a type of radioactive disintegration in which some unstable atomic nuclei spontaneously expel an alpha particle to dissipate excess energy.

Alpha decay of Radon-198 is shown as:

¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po

In the above decay from the parent nuclei, daughter nuclei (¹⁹⁴₈₄Po) and alpha particle (⁴₂He) is produced.

Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.

To know more about alpha decay, visit the below link:
https://brainly.com/question/13512293

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