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Calculate the force between a 0.006 C charge and a 0.001 C charge 4 meters apart.

Sagot :

Ryan2
[tex]F=\frac{9*10^9*6*10^{-3}*10^{-3}}{4^2}=\frac{54*10^3}{16}=3.375*10^3 \ N[/tex]
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