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what's the value of log2 (1/8) ?

Sagot :

begrajjangra75
log2(1/8)=
-log2(8)=
-(log2(2))^3=
-3log2(2)
-3
kate200468
[tex]log_aa^p=p\\------\\\\log_2 ( \frac{1}{8} ) =log_28^{-1}=log_2(2^3)^{-1}=log_22^{-3}=-3\\\\Ans.\ -3[/tex]
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